1. `A=-1-i,B=-2+3i,C=1-3i`
Find polar(A)

Solution:
Here `A=-1-i,B=-2+3i,C=1-3i`




Here, `a=-1` and `b=-1`

`:. r=sqrt((-1)^2+(-1)^2)=sqrt(1+1)=sqrt(2)=1.4142`

`theta=atan(b/a)+180` (Since `a<0`)

`:. theta=atan((-1)/(-1))+180`

`:. theta=atan(1)+180`

`:. theta=45+180`

`:. theta=225 ^circ` or `theta=(5pi)/(4)` rad = 3.927 rad

`:.` The polar form (in degree) is `1.4142*(cos(225)+i*sin(225))`

`:.` The polar form (in radian) is `1.4142*(cos((5pi)/(4))+i*sin((5pi)/(4)))`