Factor by Reverse FOIL method (Splitting the middle term of quadratic trinomials) calculator

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Solution

Solution provided by AtoZmath.com

$25x^2-36$

$x^3+27$

$x^3-64y^3$

$x^2+6x+9$

$x^2+10x+24$

$4x^2+y^2+1+4xy+4x+2y$

$x^3-3x^2-6x+8$

Example

(1) $x^2+10x+24$

The coefficients are

$a=1,b=10,c=24$

Find pair of factors whose product is

$a*c=1 * 24=24$ and sum is

$b=10$

The pairs of factors for 24 and their sums are

$1,24 : 1+24=25$

$2,12 : 2+12=14$

$3,8 : 3+8=11$

$4,6 : 4+6=10$

Factors are

$4,6$ whose product is

$4 * 6=24$ and sum is

$4+6=10$

So use

$4$ and

$6$ to split the

$10$ coefficient on the middle term

$=x^2+4x+6x+24$

$=x(x+4)+6(x+4)$

$=(x+4)(x+6)$

Factoring Polynomials Formulas

$mx + my = m(x + y)$
2.

$x^2 - y^2 = (x - y)(x + y)$
3.

$x^3 - y^3 = (x - y)(x^2 + xy + y^2)$
4.

$x^3 + y^3 = (x + y)(x^2 - xy + y^2)$
5.

$(x + y)^2 = x^2 + 2xy + y^2$
6.

$(x - y)^2 = x^2 - 2xy + y^2$
7.

$(x + y)^3 = x^3 + y^3 + 3xy(x + y)$
8.

$(x - y)^3 = x^3 - y^3 - 3xy(x - y)$
9.

$(x + y + z)^2 = x^2 + y^2 + z^2 + 2xy + 2yz + 2zx$