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Pivots of a Matrix calculator
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 1. `[[8,-6,2],[-6,7,-4],[2,-4,3]]`
2. `[[6,-2,2],[-2,3,-1],[2,-1,3]]`
3. `[[3,2,4],[2,0,2],[4,2,3]]`
4. `[[1,1,1],[-1,-3,-3],[2,4,4]]`
5. `[[2,3],[4,10]]`
6. `[[5,1],[4,2]]`
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Example1. Find Pivots of a Matrix ...
`[[8,-6,2],[-6,7,-4],[2,-4,3]]`Solution:First apply Gaussian Elimination method to find Pivots | `A` | = | | `8` | `-6` | `2` | | | `-6` | `7` | `-4` | | | `2` | `-4` | `3` | |
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`R_2 larr R_2+3/4xx R_1` | = | | `8` | `-6` | `2` | | | `0` `0=-6+3/4xx8`
`R_2 larr R_2+3/4xx R_1` | `5/2` `5/2=7+3/4xx-6`
`R_2 larr R_2+3/4xx R_1` | `-5/2` `-5/2=-4+3/4xx2`
`R_2 larr R_2+3/4xx R_1` | | | `2` | `-4` | `3` | |
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`R_3 larr R_3-1/4xx R_1` | = | | `8` | `-6` | `2` | | | `0` | `5/2` | `-5/2` | | | `0` `0=2-1/4xx8`
`R_3 larr R_3-1/4xx R_1` | `-5/2` `-5/2=-4-1/4xx-6`
`R_3 larr R_3-1/4xx R_1` | `5/2` `5/2=3-1/4xx2`
`R_3 larr R_3-1/4xx R_1` | |
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`R_3 larr R_3+ R_2` | = | | `8` | `-6` | `2` | | | `0` | `5/2` | `-5/2` | | | `0` `0=0+0`
`R_3 larr R_3+ R_2` | `0` `0=-5/2+5/2`
`R_3 larr R_3+ R_2` | `0` `0=5/2+-5/2`
`R_3 larr R_3+ R_2` | |
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Now, Pivots are the first non-zero element in each row of this eliminated matrix. Pivots are `8,5/2`
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