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Solution
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Solution provided by AtoZmath.com
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Reduced Row Echelon Form calculator | RREF calculator
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 1. `[[8,-6,2],[-6,7,-4],[2,-4,3]]`
2. `[[3,2,4],[2,0,2],[4,2,3]]`
3. `[[1,1,1],[-1,-3,-3],[2,4,4]]`
4. `[[1,2,3],[0,1,0],[2,3,1]]`
5. `[[1,2,1],[6,-1,0],[-1,-2,-1]]`
6. `[[6,-2,2],[-2,3,-1],[2,-1,3]]`
7. `[[2,3],[4,10]]`
8. `[[5,1],[4,2]]`
9. `[[6,3],[4,5]]`
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Example1. Find Reduced Row Echelon Form (RREF) ...
`[[8,-6,2],[-6,7,-4],[2,-4,3]]`Solution:Reduced row echelon form Given matrix | | | `8` | `-6` | `2` | | | `-6` | `7` | `-4` | | | `2` | `-4` | `3` | |
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`R_1 larr R_1-:8` | = | | `1` | `-3/4` | `1/4` | | | `-6` | `7` | `-4` | | | `2` | `-4` | `3` | |
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`R_2 larr R_2+6xx R_1` | = | | `1` | `-3/4` | `1/4` | | | `0` | `5/2` | `-5/2` | | | `2` | `-4` | `3` | |
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`R_3 larr R_3-2xx R_1` | = | | `1` | `-3/4` | `1/4` | | | `0` | `5/2` | `-5/2` | | | `0` | `-5/2` | `5/2` | |
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`R_2 larr R_2xx2/5` | = | | `1` | `-3/4` | `1/4` | | | `0` | `1` | `-1` | | | `0` | `-5/2` | `5/2` | |
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`R_1 larr R_1+3/4xx R_2` | = | | `1` | `0` | `-1/2` | | | `0` | `1` | `-1` | | | `0` | `-5/2` | `5/2` | |
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`R_3 larr R_3+5/2xx R_2` | = | | `1` | `0` | `-1/2` | | | `0` | `1` | `-1` | | | `0` | `0` | `0` | |
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