To determine root divisor, we have to solve divisor equation `x-5=0`
`:.` our root becomes `x=5`
Write coefficients of the dividend `x^2-10x+25` to the right and our root
`5` to the left
Step-1 : Write down the first coefficient
`1`Step-2 : Multiply our root
`5` by our last result
`1` to get
`5` [
`5` ×
`1`=
`5` ]
`5` | `1` | `-10` | `25` |
| `` | `5` | `` |
| `1` | | |
Step-3 : Add new result
`5` to the next coefficient of the dividend
`-10`, and write down the sum
`-5`, [
`(-10)` +
`5`=
`-5` ]
`5` | `1` | `-10` | `25` |
| `` | `5` | `` |
| `1` | `-5` | |
Step-4 : Multiply our root
`5` by our last result
`-5` to get
`-25` [
`5` ×
`(-5)`=
`-25` ]
`5` | `1` | `-10` | `25` |
| `` | `5` | `-25` |
| `1` | `-5` | |
Step-5 : Add new result
`-25` to the next coefficient of the dividend
`25`, and write down the sum
`0`, [
`25` +
`(-25)`=
`0` ]
`5` | `1` | `-10` | `25` |
| `` | `5` | `-25` |
| `1` | `-5` | `0` |
We have completed the table and have obtained the following coefficients
`1,-5,0`
All coefficients, except last one, are coefficients of quotient, last coefficient is remainder.
Thus quotient is `x-5` and remainder is `0`