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Method and examples
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HCF_LCM |
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Problem 3 of 11 |
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3. Find the smallest number exactly divisible by .
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Solution
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Solution provided by AtoZmath.com
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This is demo example. Please click on Find button and solution will be displayed in Solution tab (step by step)
| HCF_LCM |
3. Find the smallest number exactly divisible by 12,15,20,27 .
`"Required number" = "LCM of " 12,15,20,27 = 540`.
| 2 | 12 | | 15 | | 20 | | 27 | | 2 | 6 | | 15 | | 10 | | 27 | | 3 | 3 | | 15 | | 5 | | 27 | | 3 | 1 | | 5 | | 5 | | 9 | | 3 | 1 | | 5 | | 5 | | 3 | | 5 | 1 | | 5 | | 5 | | 1 | | | 1 | | 1 | | 1 | | 1 |
LCM of 12,15,20,27 = 2 × 2 × 3 × 3 × 3 × 5 = 540
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