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Method and examples
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Arithmetic Progression |
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Problem 7 of 19 |
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7. For arithemetic progression addition of terms is and their multiplication is , then that numbers
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Solution
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Solution provided by AtoZmath.com
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This is demo example. Please click on Find button and solution will be displayed in Solution tab (step by step)
| Arithmetic Progression |
7. For arithemetic progression addition of 3 terms is 27 and their multiplication is 648 , then that numbers
Let the terms are `a-d, a, a+d`
Addition of this terms is `27`
`=> (a-d) + a + (a+d) = 27`
`=> 3 a = 27`
`=> a = 27/3 = 9`
Multiplication of this terms is `648`
`=> (a-d) × a × (a+d) = 648`
`=> (9-d) × 9 × (9+d) = 648`
`=> (81 - d^2) = 72`
`=> d^2 = 9`
`=> d = +- 3`
`d = +3 =>` Required terms : `9 - 3, 9, 9 + 3 => 6, 9, 12`
`d = -3 =>` Required terms : `9-(-3), 9, 9-3 => 12, 9, 6`
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