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1. Bisection method example ( Enter your problem )
  1. Algorithm & Example-1 `f(x)=x^3-x-1`
  2. Example-2 `f(x)=2x^3-2x-5`
  3. Example-3 `x=sqrt(12)`
  4. Example-4 `x=root(3)(48)`
  5. Example-5 `f(x)=x^3+2x^2+x-1`
Other related methods
  1. Bisection method
  2. False Position method (regula falsi method)
  3. Newton Raphson method
  4. Fixed Point Iteration method
  5. Secant method
  6. Muller method
  7. Halley's method
  8. Steffensen's method
  9. Ridder's method

3. Example-3 `x=sqrt(12)`
(Previous example)
5. Example-5 `f(x)=x^3+2x^2+x-1`
(Next example)

4. Example-4 `x=root(3)(48)`





Find `root(3)(48)` using Bisection method

Solution:
Let `x=48^(1/3)`

`:.x^3=48`

`:.x^3-48=0`

i.e. `f(x)=x^3-48`

Here
`x`01234
`f(x)`-48-47-40-2116



`1^(st)` iteration :

Here `f(3) = -21 < 0` and `f(4) = 16 > 0`

`:.` Now, Root lies between `3` and `4`

`x_0=(3+4)/2=3.5`

`f(x_0)=f(3.5)=3.5^3-48=-5.125 < 0`


`2^(nd)` iteration :

Here `f(3.5) = -5.125 < 0` and `f(4) = 16 > 0`

`:.` Now, Root lies between `3.5` and `4`

`x_1=(3.5+4)/2=3.75`

`f(x_1)=f(3.75)=3.75^3-48=4.7344 > 0`


`3^(rd)` iteration :

Here `f(3.5) = -5.125 < 0` and `f(3.75) = 4.7344 > 0`

`:.` Now, Root lies between `3.5` and `3.75`

`x_2=(3.5+3.75)/2=3.625`

`f(x_2)=f(3.625)=3.625^3-48=-0.3652 < 0`


`4^(th)` iteration :

Here `f(3.625) = -0.3652 < 0` and `f(3.75) = 4.7344 > 0`

`:.` Now, Root lies between `3.625` and `3.75`

`x_3=(3.625+3.75)/2=3.6875`

`f(x_3)=f(3.6875)=3.6875^3-48=2.1414 > 0`


`5^(th)` iteration :

Here `f(3.625) = -0.3652 < 0` and `f(3.6875) = 2.1414 > 0`

`:.` Now, Root lies between `3.625` and `3.6875`

`x_4=(3.625+3.6875)/2=3.6562`

`f(x_4)=f(3.6562)=3.6562^3-48=0.8773 > 0`


`6^(th)` iteration :

Here `f(3.625) = -0.3652 < 0` and `f(3.6562) = 0.8773 > 0`

`:.` Now, Root lies between `3.625` and `3.6562`

`x_5=(3.625+3.6562)/2=3.6406`

`f(x_5)=f(3.6406)=3.6406^3-48=0.2534 > 0`


`7^(th)` iteration :

Here `f(3.625) = -0.3652 < 0` and `f(3.6406) = 0.2534 > 0`

`:.` Now, Root lies between `3.625` and `3.6406`

`x_6=(3.625+3.6406)/2=3.6328`

`f(x_6)=f(3.6328)=3.6328^3-48=-0.0566 < 0`


`8^(th)` iteration :

Here `f(3.6328) = -0.0566 < 0` and `f(3.6406) = 0.2534 > 0`

`:.` Now, Root lies between `3.6328` and `3.6406`

`x_7=(3.6328+3.6406)/2=3.6367`

`f(x_7)=f(3.6367)=3.6367^3-48=0.0982 > 0`


`9^(th)` iteration :

Here `f(3.6328) = -0.0566 < 0` and `f(3.6367) = 0.0982 > 0`

`:.` Now, Root lies between `3.6328` and `3.6367`

`x_8=(3.6328+3.6367)/2=3.6348`

`f(x_8)=f(3.6348)=3.6348^3-48=0.0208 > 0`


`10^(th)` iteration :

Here `f(3.6328) = -0.0566 < 0` and `f(3.6348) = 0.0208 > 0`

`:.` Now, Root lies between `3.6328` and `3.6348`

`x_9=(3.6328+3.6348)/2=3.6338`

`f(x_9)=f(3.6338)=3.6338^3-48=-0.0179 < 0`


`11^(th)` iteration :

Here `f(3.6338) = -0.0179 < 0` and `f(3.6348) = 0.0208 > 0`

`:.` Now, Root lies between `3.6338` and `3.6348`

`x_10=(3.6338+3.6348)/2=3.6343`

`f(x_10)=f(3.6343)=3.6343^3-48=0.0014 > 0`


`12^(th)` iteration :

Here `f(3.6338) = -0.0179 < 0` and `f(3.6343) = 0.0014 > 0`

`:.` Now, Root lies between `3.6338` and `3.6343`

`x_11=(3.6338+3.6343)/2=3.634`

`f(x_11)=f(3.634)=3.634^3-48=-0.0082 < 0`


`13^(th)` iteration :

Here `f(3.634) = -0.0082 < 0` and `f(3.6343) = 0.0014 > 0`

`:.` Now, Root lies between `3.634` and `3.6343`

`x_12=(3.634+3.6343)/2=3.6342`

`f(x_12)=f(3.6342)=3.6342^3-48=-0.0034 < 0`


`14^(th)` iteration :

Here `f(3.6342) = -0.0034 < 0` and `f(3.6343) = 0.0014 > 0`

`:.` Now, Root lies between `3.6342` and `3.6343`

`x_13=(3.6342+3.6343)/2=3.6342`

`f(x_13)=f(3.6342)=3.6342^3-48=-0.001 < 0`


`15^(th)` iteration :

Here `f(3.6342) = -0.001 < 0` and `f(3.6343) = 0.0014 > 0`

`:.` Now, Root lies between `3.6342` and `3.6343`

`x_14=(3.6342+3.6343)/2=3.6342`

`f(x_14)=f(3.6342)=3.6342^3-48=0.0002 > 0`


Approximate root of the equation `x^3-48=0` using Bisection method is `3.6342` (After 15 iterations)

`n``a``f(a)``b``f(b)``c=(a + b)/2``f(c)`Update
13-214163.5-5.125`a = c`
23.5-5.1254163.754.7344`b = c`
33.5-5.1253.754.73443.625-0.3652`a = c`
43.625-0.36523.754.73443.68752.1414`b = c`
53.625-0.36523.68752.14143.65620.8773`b = c`
63.625-0.36523.65620.87733.64060.2534`b = c`
73.625-0.36523.64060.25343.6328-0.0566`a = c`
83.6328-0.05663.64060.25343.63670.0982`b = c`
93.6328-0.05663.63670.09823.63480.0208`b = c`
103.6328-0.05663.63480.02083.6338-0.0179`a = c`
113.6338-0.01793.63480.02083.63430.0014`b = c`
123.6338-0.01793.63430.00143.634-0.0082`a = c`
133.634-0.00823.63430.00143.6342-0.0034`a = c`
143.6342-0.00343.63430.00143.6342-0.001`a = c`
153.6342-0.0013.63430.00143.63420.0002`b = c`





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3. Example-3 `x=sqrt(12)`
(Previous example)
5. Example-5 `f(x)=x^3+2x^2+x-1`
(Next example)





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