1. Find Mean deviation about Median from the following ungrouped data
`85,96,76,108,85,80,100,85,70,95`

Solution:
Median :
Observations in the ascending order are :
`70,76,80,85,85,85,95,96,100,108`

Here, `n=10` is even.

`M=(text{Value of } (n/2)^(th) text{ observation} + text{Value of } (n/2 + 1)^(th) text{ observation})/2`

`=(text{Value of } (10/2)^(th) text{ observation} + text{Value of } (10/2 + 1)^(th) text{ observation})/2`

`=(text{Value of }5^(th) text{ observation} + text{Value of }6^(th) text{ observation})/2`

`=(85 + 85)/2`

`=85`

`x`	`|x - M| = |x - 85|`
85	0
96	11
76	9
108	23
85	0
80	5
100	15
85	0
70	15
95	10
---	---
`880`	`88`

Mean deviation of Median
`delta bar x = (sum |x - M|)/n`

`delta bar x = 88/10`

`delta bar x = 8.8`


Coefficient of Mean deviation `=(delta bar x)/(bar x)`

`=8.8/85`

`=0.1035`

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2. Find Mean deviation about Median from the following ungrouped data
`69,66,67,69,64,63,65,68,72`

Solution:
Median :
Observations in the ascending order are :
`63,64,65,66,67,68,69,69,72`

Here, `n=9` is odd.

`M=` value of `((n+1)/2)^(th)` observation

`=` value of `((9+1)/2)^(th)` observation

`=` value of `5^(th)` observation

`=67`

`x`	`|x - M| = |x - 67|`
69	2
66	1
67	0
69	2
64	3
63	4
65	2
68	1
72	5
---	---
`603`	`20`

Mean deviation of Median
`delta bar x = (sum |x - M|)/n`

`delta bar x = 20/9`

`delta bar x = 2.2222`


Coefficient of Mean deviation `=(delta bar x)/(bar x)`

`=2.2222/67`

`=0.0332`

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