5. Gauss Seidel method example ( Enter your problem )
  1. Example `2x+y=8,x+2y=1`
  2. Example `2x+5y=16,3x+y=11`
  3. Example `2x+y+z=5,3x+5y+2z=15,2x+y+4z=8`
  4. Example `x+y+z=7,x+2y+2z=13,x+3y+z=13`
Other related methods
  1. Inverse Matrix method
  2. Cramer's Rule method
  3. Gauss-Jordan Elimination method
  4. Gauss Elimination Back Substitution method
  5. Gauss Seidel method
  6. Gauss Jacobi method
  7. Elimination method
  8. LU decomposition using Gauss Elimination method
  9. LU decomposition using Doolittle's method
  10. LU decomposition using Crout's method
  11. Cholesky decomposition method
  12. SOR (Successive over-relaxation) method
  13. Relaxation method

4. Gauss Elimination Back Substitution method
(Previous method)
2. Example `2x+5y=16,3x+y=11`
(Next example)

1. Example `2x+y=8,x+2y=1`





Solve Equations 2x+y=8,x+2y=1 using Gauss Seidel method

Solution:
Total Equations are `2`

`2x+y=8`

`x+2y=1`


From the above equations
`x_(k+1)=1/2(8-y_(k))`

`y_(k+1)=1/2(1-x_(k+1))`

Initial gauss `(x,y) = (0,0)`

Solution steps are
`1^(st)` Approximation

`x_1=1/2[8-(0)]=1/2[8]=4`

`y_1=1/2[1-(4)]=1/2[-3]=-1.5`

`2^(nd)` Approximation

`x_2=1/2[8-(-1.5)]=1/2[9.5]=4.75`

`y_2=1/2[1-(4.75)]=1/2[-3.75]=-1.875`

`3^(rd)` Approximation

`x_3=1/2[8-(-1.875)]=1/2[9.875]=4.9375`

`y_3=1/2[1-(4.9375)]=1/2[-3.9375]=-1.9688`

`4^(th)` Approximation

`x_4=1/2[8-(-1.9688)]=1/2[9.9688]=4.9844`

`y_4=1/2[1-(4.9844)]=1/2[-3.9844]=-1.9922`

`5^(th)` Approximation

`x_5=1/2[8-(-1.9922)]=1/2[9.9922]=4.9961`

`y_5=1/2[1-(4.9961)]=1/2[-3.9961]=-1.998`

`6^(th)` Approximation

`x_6=1/2[8-(-1.998)]=1/2[9.998]=4.999`

`y_6=1/2[1-(4.999)]=1/2[-3.999]=-1.9995`

`7^(th)` Approximation

`x_7=1/2[8-(-1.9995)]=1/2[9.9995]=4.9998`

`y_7=1/2[1-(4.9998)]=1/2[-3.9998]=-1.9999`


Solution By Gauss Seidel Method.
`x=4.9998~=5`

`y=-1.9999~=-2`

Iterations are tabulated as below
Iterationxy
14-1.5
24.75-1.875
34.9375-1.9688
44.9844-1.9922
54.9961-1.998
64.999-1.9995
74.9998-1.9999



This material is intended as a summary. Use your textbook for detail explanation.
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4. Gauss Elimination Back Substitution method
(Previous method)
2. Example `2x+5y=16,3x+y=11`
(Next example)





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