1. Solve Equations 2x+5y=21,x+2y=8 using Gauss-Jordan Elimination method
Solution:
Total Equations are `2`
`2x+5y=21 -> (1)`
`x+2y=8 -> (2)`
Converting given equations into matrix form
`R_1 larr R_1-:2`
= | | `1` `1=2-:2` `R_1 larr R_1-:2` | `5/2` `5/2=5-:2` `R_1 larr R_1-:2` | | `21/2` `21/2=21-:2` `R_1 larr R_1-:2` | | | `1` | `2` | | `8` | |
|
`R_2 larr R_2- R_1`
= | | `1` | `5/2` | | `21/2` | | | `0` `0=1-1` `R_2 larr R_2- R_1` | `-1/2` `-1/2=2-5/2` `R_2 larr R_2- R_1` | | `-5/2` `-5/2=8-21/2` `R_2 larr R_2- R_1` | |
|
`R_2 larr R_2xx-2`
= | | `1` | `5/2` | | `21/2` | | | `0` `0=0xx-2` `R_2 larr R_2xx-2` | `1` `1=-1/2xx-2` `R_2 larr R_2xx-2` | | `5` `5=-5/2xx-2` `R_2 larr R_2xx-2` | |
|
`R_1 larr R_1-5/2xx R_2`
= | | `1` `1=1-5/2xx0` `R_1 larr R_1-5/2xx R_2` | `0` `0=5/2-5/2xx1` `R_1 larr R_1-5/2xx R_2` | | `-2` `-2=21/2-5/2xx5` `R_1 larr R_1-5/2xx R_2` | | | `0` | `1` | | `5` | |
|
`i.e.`
`x=-2`
`y=5`
Solution By Gauss jordan elimination method.
`x = -2`
`y = 5`
This material is intended as a summary. Use your textbook for detail explanation.
Any bug, improvement, feedback then