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3. Gauss-Jordan Elimination method example ( Enter your problem )
  1. Example `2x+5y=21,x+2y=8`
  2. Example `2x+5y=16,3x+y=11`
  3. Example `2x+3y-z=5,3x+2y+z=10,x-5y+3z=0`
  4. Example `x+y+z=3,2x-y-z=3,x-y+z=9`

1. Example `2x+5y=21,x+2y=8`





1. Solve Equations 2x+5y=21,x+2y=8 using Gauss-Jordan Elimination method

Solution:
Total Equations are `2`

`2x+5y=21 -> (1)`

`x+2y=8 -> (2)`

Converting given equations into matrix form
`2``5``21`
`1``2``8`


`R_1 larr R_1-:2`

 = 
 `1` `1=2-:2`
`R_1 larr R_1-:2`
 `5/2` `5/2=5-:2`
`R_1 larr R_1-:2`
 `21/2` `21/2=21-:2`
`R_1 larr R_1-:2`
`1``2``8`


`R_2 larr R_2- R_1`

 = 
`1``5/2``21/2`
 `0` `0=1-1`
`R_2 larr R_2- R_1`
 `-1/2` `-1/2=2-5/2`
`R_2 larr R_2- R_1`
 `-5/2` `-5/2=8-21/2`
`R_2 larr R_2- R_1`


`R_2 larr R_2xx-2`

 = 
`1``5/2``21/2`
 `0` `0=0xx-2`
`R_2 larr R_2xx-2`
 `1` `1=-1/2xx-2`
`R_2 larr R_2xx-2`
 `5` `5=-5/2xx-2`
`R_2 larr R_2xx-2`


`R_1 larr R_1-5/2xx R_2`

 = 
 `1` `1=1-5/2xx0`
`R_1 larr R_1-5/2xx R_2`
 `0` `0=5/2-5/2xx1`
`R_1 larr R_1-5/2xx R_2`
 `-2` `-2=21/2-5/2xx5`
`R_1 larr R_1-5/2xx R_2`
`0``1``5`


`i.e.`

`x=-2`

`y=5`

Solution By Gauss jordan elimination method.
`x = -2`

`y = 5`




This material is intended as a summary. Use your textbook for detail explanation.
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