Home > Matrix & Vector > Solving Systems of linear equations > Solving systems of linear equations using Gauss-Jordan Elimination method example

3. Gauss-Jordan Elimination method example ( Enter your problem )
  1. Example `2x+5y=21,x+2y=8`
  2. Example `2x+5y=16,3x+y=11`
  3. Example `2x+3y-z=5,3x+2y+z=10,x-5y+3z=0`
  4. Example `x+y+z=3,2x-y-z=3,x-y+z=9`

3. Example `2x+3y-z=5,3x+2y+z=10,x-5y+3z=0`





Solve Equations 2x+3y-z=5,3x+2y+z=10,x-5y+3z=0 using Gauss-Jordan Elimination method

Solution:
Total Equations are `3`

`2x+3y-z=5 -> (1)`

`3x+2y+z=10 -> (2)`

`x-5y+3z=0 -> (3)`

Converting given equations into matrix form
`2``3``-1``5`
`3``2``1``10`
`1``-5``3``0`


`R_1 larr R_1-:2`

 = 
`1``1.5``-0.5``2.5`
`3``2``1``10`
`1``-5``3``0`


`R_2 larr R_2-3xx R_1`

 = 
`1``1.5``-0.5``2.5`
`0``-2.5``2.5``2.5`
`1``-5``3``0`


`R_3 larr R_3- R_1`

 = 
`1``1.5``-0.5``2.5`
`0``-2.5``2.5``2.5`
`0``-6.5``3.5``-2.5`


`R_2 larr R_2xx-0.4`

 = 
`1``1.5``-0.5``2.5`
`0``1``-1``-1`
`0``-6.5``3.5``-2.5`


`R_1 larr R_1-1.5xx R_2`

 = 
`1``0``1``4`
`0``1``-1``-1`
`0``-6.5``3.5``-2.5`


`R_3 larr R_3+6.5xx R_2`

 = 
`1``0``1``4`
`0``1``-1``-1`
`0``0``-3``-9`


`R_3 larr R_3-:-3`

 = 
`1``0``1``4`
`0``1``-1``-1`
`0``0``1``3`


`R_1 larr R_1- R_3`

 = 
`1``0``0``1`
`0``1``-1``-1`
`0``0``1``3`


`R_2 larr R_2+ R_3`

 = 
`1``0``0``1`
`0``1``0``2`
`0``0``1``3`


`i.e.`

`x=1`

`y=2`

`z=3`

Solution By Gauss jordan elimination method
`x=1,y=2 and z=3`






This material is intended as a summary. Use your textbook for detail explanation.
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