Home > Matrix & Vector > Solving Systems of linear equations > Solving systems of linear equations using Inverse Matrix method example

1. Inverse Matrix method example ( Enter your problem )
  1. Example `2x+5y=21,x+2y=8`
  2. Example `2x+5y=16,3x+y=11`
  3. Example `2x+3y-z=5,3x+2y+z=10,x-5y+3z=0`
  4. Example `x+y+z=3,2x-y-z=3,x-y+z=9`

1. Example `2x+5y=21,x+2y=8`





1. Solve Equations 2x+5y=21,x+2y=8 using Inverse Matrix method

Solution:
Here `2x+5y=21`
`x+2y=8`

Now converting given equations into matrix form
`[[2,5],[1,2]] [[x],[y]]=[[21],[8]]`

Now, A = `[[2,5],[1,2]]`, X = `[[x],[y]]` and B = `[[21],[8]]`

`:. AX = B`

`:. X = A^-1 B`

`|A|` = 
 `2`  `5` 
 `1`  `2` 


`=2 × 2 - 5 × 1`

`=4 -5`

`=-1`


`"Here, " |A| = -1 != 0`

`:. A^(-1) " is possible."`

`Adj(A)` = 
Adj
`2``5`
`1``2`


 = 
 + 
 `2` 
 - 
 `1` 
 - 
 `5` 
 + 
 `2` 
T


 = 
`+(2)``-(1)`
`-(5)``+(2)`
T


 = 
`2``-1`
`-5``2`
T


 = 
`2``-5`
`-1``2`



`"Now, "A^(-1)=1/|A| × Adj(A)`

`"Here, "X = A^(-1) × B`

`:. X = 1/|A| × Adj(A) × B`

 = `1/(-1)` ×
`2``-5`
`-1``2`
×
`21`
`8`


 = `1/(-1)` ×
`2×21-5×8`
`-1×21+2×8`


 = `1/(-1)` ×
`2`
`-5`


 = 
`-2`
`5`


`:.[[x],[y]]=[[-2],[5]]`

`:. x=-2, y=5`




This material is intended as a summary. Use your textbook for detail explanation.
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