2. Non parametric test - Kruskal-wallis test for the following data
24,32,39,34,30,40,36,38
28,31,35,22,38,28,32,28
34,31,28,24,31,26,28,34, Significance Level `alpha=0.05` and One-tailed test
Solution:
Step-1: Take the hypothesis
Null Hypothesis `H_0` : All groups are equal
Alternative Hypothesis `H_1` : Atleast one group is not equal
Step-2: Ranking all group values
Size in Ascending Order | Rank | Name of related sample A for sample-1 B for sample-2 C for sample-3 | Rank for A | Rank for B | Rank for C |
22 | 1 | B | | 1 | |
24 | 2.5 | C | | | 2.5 |
24 | 2.5 | A | 2.5 | | |
26 | 4 | C | | | 4 |
28 | 7 | C | | | 7 |
28 | 7 | C | | | 7 |
28 | 7 | B | | 7 | |
28 | 7 | B | | 7 | |
28 | 7 | B | | 7 | |
30 | 10 | A | 10 | | |
31 | 12 | C | | | 12 |
31 | 12 | C | | | 12 |
31 | 12 | B | | 12 | |
32 | 14.5 | B | | 14.5 | |
32 | 14.5 | A | 14.5 | | |
34 | 17 | C | | | 17 |
34 | 17 | C | | | 17 |
34 | 17 | A | 17 | | |
35 | 19 | B | | 19 | |
36 | 20 | A | 20 | | |
38 | 21.5 | B | | 21.5 | |
38 | 21.5 | A | 21.5 | | |
39 | 23 | A | 23 | | |
40 | 24 | A | 24 | | |
Total | | | 132.5 | 89 | 78.5 |
The rank total for A is `R_1=132.5`
The rank total for B is `R_2=89`
The rank total for C is `R_3=78.5`
Step-3: Compute test statistic
`sum R_j^2/n_j=(132.5)^2/8+(89)^2/8+(78.5)^2/8=3954.9375`
n = total number of samples = 24
`H=12/(n(n+1)) sum R_j^2/n_j - 3(n+1)`
`=12/(24(24+1)) (3954.9375) - 3(24+1)`
`=12/600 * (3954.9375) - 75`
`=4.0987`
Step-4: `alpha=0.05`
Step-5: Compute the degrees of freedom (df).
`df=(3-1)=2`
Step-6:
The Critical value of chi-square is `chi^2(0.05,2)=5.9915`
Since the computed `H`(4.0987) < critical `chi^2`(5.9915)
So we accept the null hypothesis (`H_0`) and conclude that all groups are identical.
This material is intended as a summary. Use your textbook for detail explanation.
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