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7. Bessel's formula for Derivatives (Numerical Differentiation) example ( Enter your problem )
  1. Formula & Example-1
  2. Example-2

1. Formula & Example-1





Formula
1. For `x=x_0`
`[(dy)/(dx)]_(x=x_0) = 1/h * [Delta y_0 - 1/4 * (Delta^2 y_(0) + Delta^2 y_(-1)) + 1/12 Delta^3 y_(-1) + 1/24 * (Delta^4 y_(-1) + Delta^4 y_(-2)) - 1/120 Delta^5 y_(-2) - 1/120 * (Delta^6 y_(-2) + Delta^6 y_(-3)) + ...]`
`[(d^2y)/(dx^2)]_(x=x_0) = 1/h^2 * [1/2 * (Delta^2 y_(0) + Delta^2 y_(-1)) - 1/2 Delta^3 y_(-1) - 1/24 * (Delta^4 y_(-1) + Delta^4 y_(-2)) + ...]`

Examples
1. Using Bessel's formula to find solution
xf(x)
7.470.193
7.480.195
7.490.198
7.500.201
7.510.203
7.520.206
7.530.208

x = 7.5


Solution:
Bessel's formula (central difference formula).
The value of table for `x` and `y`

x7.477.487.497.57.517.527.53
y0.1930.1950.1980.2010.2030.2060.208

Difference table is
xy`Deltay``Delta^2y``Delta^3y``Delta^4y``Delta^5y``Delta^6y`
7.470.193
0.002
7.480.1950.001
0.003-0.001
7.490.19800
0.003-0.0010.003
7.50.201-0.0010.003-0.01
0.0020.002-0.007
7.510.2030.001-0.004
0.003-0.002
7.520.206-0.001
0.002
7.530.208


The value of `x` at you want to find `f(x) : x_0 = 7.5`

`h = x_1 - x_0 = 7.48 - 7.47 = 0.01`


Bessel's Formula is
`[(dy)/(dx)]_(x=x_0) = 1/h * [Delta y_0 - 1/4 * (Delta^2 y_(0) + Delta^2 y_(-1)) + 1/12 Delta^3 y_(-1) + 1/24 * (Delta^4 y_(-1) + Delta^4 y_(-2)) - 1/120 Delta^5 y_(-2) - 1/120 * (Delta^6 y_(-2) + Delta^6 y_(-3)) + ...]`

`:.[(dy)/(dx)]_(x=7.5) = 1/0.01 * [0.002 - 1/4 * (0.001 -0.001) + 1/12 * (0.002) + 1/24 * (-0.004 +0.003) - 1/120 * (-0.007) - 1/120 * (0 -0.01) + ...]`

`:.[(dy)/(dx)]_(x=7.5) = 1/0.01 * [0.002+0+0.0001666667-0.0000416667+0.0000583333+0.0000833333]`

`:.[(dy)/(dx)]_(x=7.5) = 0.2267`


`[(d^2y)/(dx^2)]_(x=x_0) = 1/h^2 * [1/2 * (Delta^2 y_(0) + Delta^2 y_(-1)) - 1/3 Delta^3 y_(-1) - 1/24 * (Delta^4 y_(-1) + Delta^4 y_(-2)) + 1/24 Delta^5 y_(-2) + 1/180 * (Delta^6 y_(-2) + Delta^6 y_(-3)) + ...]`

`:.[(d^2y)/(dx^2)]_(x=7.5) = 1/0.0001 * [1/2 * (0.001 -0.001) - 1/2 * (0.002) - 1/24 * (-0.004 +0.003) + 1/24 * (-0.007) + 1/180 * (0 -0.01)]`

`:.[(d^2y)/(dx^2)]_(x=7.5) = 1/0.0001 * [0-0.001+0.0000416667-0.0002916667-0.0000555556]`

`:.[(d^2y)/(dx^2)]_(x=7.5) = -13.0556`




This material is intended as a summary. Use your textbook for detail explanation.
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