Find the approximated integral value of an equation 1/x using Right Riemann Sum
a = 1 and b = 2
Step value (h) = 0.25

Solution:
Equation is `f(x)=(1)/(x)`

`a=1`

`b=2`

The value of table for `x` and `f(x)`

`x`	`f(x)`
`x_0=1`	`f(x_(0))=f(1)=1`
`x_1=1.25`	`f(x_(1))=f(1.25)=0.8`
`x_2=1.5`	`f(x_(2))=f(1.5)=0.6667`
`x_3=1.75`	`f(x_(3))=f(1.75)=0.5714`
`x_4=2`	`f(x_(4))=f(2)=0.5`

Method-1:
Using Right Riemann Sum


`int f(x) dx=Delta x xx(f(x_(1))+f(x_(2))+f(x_(3))+f(x_(4)))`

`=0.25xx(0.8+0.6667+0.5714+0.5)`

`=0.25xx(2.5381)`

`=0.6345`

Solution by Right Riemann Sum is `0.6345`

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