1. Find Solution of an equation 1/x using Weddle's rule
x1 = 1 and x2 = 2
N = 6
Solution:
Equation is `f(x) = 1/x`.
`h = (b-a)/N`
`h = (2 - 1) / 6 = 0.1667`
The value of table for `x` and `y`
| x | 1 | 1.1667 | 1.3333 | 1.5 | 1.6667 | 1.8333 | 2 |
|---|
| y | 1 | 0.8571 | 0.75 | 0.6667 | 0.6 | 0.5455 | 0.5 |
|---|
Using Weddle's Rule
`int y dx = (3h)/10 [y_0+5y_1+y_2+6y_3+y_4+5y_5+y_6]`
`int y dx = (3xx0.1667)/10 [1 + 5xx0.8571 + 0.75 + 6xx0.6667 + 0.6 + 5xx0.5455 + 0.5]`
`int y dx = 0.6931`
Solution by Weddle's Rule is `0.6931`
2. Find Solution of an equation 1/(x+1) using Weddle's rule
x1 = 0 and x2 = 6
Step value (h) = 1
Solution:
Equation is `f(x) = 1/(x+1)`.
The value of table for `x` and `y`
| x | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
|---|
| y | 1 | 0.5 | 0.3333 | 0.25 | 0.2 | 0.1667 | 0.1429 |
|---|
Using Weddle's Rule
`int y dx = (3h)/10 [y_0+5y_1+y_2+6y_3+y_4+5y_5+y_6]`
`int y dx = (3xx1)/10 [1 + 5xx0.5 + 0.3333 + 6xx0.25 + 0.2 + 5xx0.1667 + 0.1429]`
`int y dx = 1.9529`
Solution by Weddle's Rule is `1.9529`
This material is intended as a summary. Use your textbook for detail explanation.
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