Home > Numerical methods > Numerical Interpolation > Bessel's interpolation formula example

9. Bessel's Interpolation formula example ( Enter your problem )
  1. Formula & Example-1 (table data)
  2. Example-2 (table data)
  3. Example-3 (table data)
  4. Example-4 (table data)

1. Formula & Example-1 (table data)





Formula
Bessel's formula
`p = (x - x_0)/h`
`y_p=(y_0+y_1)/2+(p-1/2)*Delta y_0 + (p(p-1))/(2!) * (Delta^2y_(-1)+Delta^2y_(0))/2 + ((p-1/2)p(p-1))/(3!) * Delta^3y_(-1) + ((p+1)p(p-1)(p-2))/(4!) * (Delta^4y_(-2)+Delta^4y_(-1))/2 + ((p-1/2)(p+1)p(p-1)(p-2))/(5!) * Delta^5y_(-2) + ...`

Examples
1. Find Solution using Bessel's formula
xf(x)
202854
243162
283544
323992

x = 25


Solution:
The value of table for `x` and `y`

x20242832
y2854316235443992

Bessel's method to find solution

`h=24-20=4`

Taking `x_0=24` then `p=(x-x_0)/h=(x-24)/4`

The difference table is
`x``p=(x-24)/4``y``Deltay``Delta^2y``Delta^3y`
20-12854
308
240316274
382-8
281354466
448
3223992


`x = 25`

`p = (x - x_0)/h = (25 - 24)/4 = 0.25`

`y_0=3162, Delta y_0=382,Delta^2y_(-1)=74,Delta^3y_(-1)=-8`

Bessel's formula is
`y_p=(y_0+y_1)/2+(p-1/2)*Delta y_0 + (p(p-1))/(2!) * (Delta^2y_(-1)+Delta^2y_(0))/2 + ((p-1/2)p(p-1))/(3!) * Delta^3y_(-1)`

`y_(0.25) = (3162+3544)/2 + (0.25-1/2)*(382) + (0.25(0.25-1))/(2)*((74+66))/2 + ((0.25-1/2)0.25(0.25-1))/(6)*(-8)`

`y_(0.25)=3353-95.5 -6.5625 -0.0625`

`y_(0.25)=3250.875`


Solution of Bessel's interpolation is `y(25) = 3250.875`




This material is intended as a summary. Use your textbook for detail explanation.
Any bug, improvement, feedback then Submit Here





Share this solution or page with your friends.
 
 
Copyright © 2026. All rights reserved. Terms, Privacy
 
 

.