Find y(0.2) for `y'=-y`, `x_0=0, y_0=1`, with step length 0.1 using Euler method (1st order derivative)

Solution:
Given `y'=-y, y(0)=1, h=0.1, y(0.2)=?`

Euler method
`y_1=y_0+hf(x_0,y_0)=1+(0.1)f(0,1)=1+(0.1)*(-1)=1+(-0.1)=0.9`

`y_2=y_1+hf(x_1,y_1)=0.9+(0.1)f(0.1,0.9)=0.9+(0.1)*(-0.9)=0.9+(-0.09)=0.81`

`:.y(0.2)=0.81`

`n`	`x_n`	`y_n`	`x_(n+1)`	`y_(n+1)`
0	0	1	0.1	0.9
1	0.1	0.9	0.2	0.81

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