Find y(0.2) for `y''=-4z-4y`, `x_0=0, y_0=0, z_0=1`, with step length 0.1 using Runge-Kutta 2 method (second order differential equation) Solution:Given `y^('')=-4z-4y, y(0)=0, y'(0)=1, h=0.1, y(0.2)=?`
put `(dy)/(dx)=z` and differentiate w.r.t. x, we obtain `(d^2y)/(dx^2)=(dz)/(dx)`
We have system of equations
`(dy)/(dx)=z=f(x,y,z)`
`(dz)/(dx)=-4z-4y=g(x,y,z)`
Method-1 : Using formula `k_2=f(x_0+h,y_0+hk_1,z_0+hl_1)`Second order Runge-Kutta (RK2) method for second order differential equation formula
`k_1=f(x_n,y_n,z_n)`
`l_1=g(x_n,y_n,z_n)`
`k_2=f(x_n+h,y_n+hk_1,z_n+hl_1)`
`l_2=g(x_n+h,y_n+hk_1,z_n+hl_1)`
`y_(n+1)=y_n+(h(k_1+k_2))/2`
`z_(n+1)=z_n+(h(l_1+l_2))/2`
for `n=0,x_0=0,y_0=0,z_0=1`
`k_1=f(x_0,y_0,z_0)`
`=f(0,0,1)`
`=1`
`l_1=g(x_0,y_0,z_0)`
`=g(0,0,1)`
`=-4`
`k_2=f(x_0+h,y_0+hk_1,z_0+hl_1)`
`=f(0.1,0.1,0.6)`
`=0.6`
`l_2=g(x_0+h,y_0+hk_1,z_0+hl_1)`
`=g(0.1,0.1,0.6)`
`=-2.8`
`y_1=y_0+(h(k_1+k_2))/2`
`=0+0.08`
`=0.08`
`z_1=z_0+(h(l_1+l_2))/2`
`=1-0.34`
`=0.66`
`x_1=x_0+h=0+0.1=0.1`
for `n=1,x_1=0.1,y_1=0.08,z_1=0.66`
`k_1=f(x_1,y_1,z_1)`
`=f(0.1,0.08,0.66)`
`=0.66`
`l_1=g(x_1,y_1,z_1)`
`=g(0.1,0.08,0.66)`
`=-2.96`
`k_2=f(x_1+h,y_1+hk_1,z_1+hl_1)`
`=f(0.2,0.146,0.364)`
`=0.364`
`l_2=g(x_1+h,y_1+hk_1,z_1+hl_1)`
`=g(0.2,0.146,0.364)`
`=-2.04`
`y_2=y_1+(h(k_1+k_2))/2`
`=0.08+0.0512`
`=0.1312`
`x_2=x_1+h=0.1+0.1=0.2`
`:.y(0.2)=0.1312`
| `n` | `x_n` | `y_n` | `z_n` | `k_1` | `l_1` | `k_2` | `l_2` | `x_(n+1)` | `y_(n+1)` | `z_(n+1)` |
| 0 | 0 | 0 | 1 | 1 | -4 | 0.6 | -2.8 | 0.1 | 0.08 | 0.66 |
| 1 | 0.1 | 0.08 | 0.66 | 0.66 | -2.96 | 0.364 | -2.04 | 0.2 | 0.1312 | |
Method-2 : Using formula `k_2=f(x_0+h/2,y_0+(hk_1)/2,z_0+(hl_1)/2)`Second order Runge-Kutta (RK2) method for second order differential equation formula
`k_1=f(x_n,y_n,z_n)`
`l_1=g(x_n,y_n,z_n)`
`k_2=f(x_n+h/2,y_n+(hk_1)/2,z_n+(hl_1)/2)`
`l_2=g(x_n+h/2,y_n+(hk_1)/2,z_n+(hl_1)/2)`
`y_(n+1)=y_n+hk_2`
`z_(n+1)=z_n+hl_2`
for `n=0,x_0=0,y_0=0,z_0=1`
`k_1=f(x_0,y_0,z_0)`
`=f(0,0,1)`
`=1`
`l_1=g(x_0,y_0,z_0)`
`=g(0,0,1)`
`=-4`
`k_2=f(x_0+h/2,y_0+(hk_1)/2,z_0+(hl_1)/2)`
`=f(0.05,0.05,0.8)`
`=0.8`
`l_2=g(x_0+h/2,y_0+(hk_1)/2,z_0+(hl_1)/2)`
`=g(0.05,0.05,0.8)`
`=-3.4`
`y_1=y_0+hk_2`
`=0+0.08`
`=0.08`
`z_1=z_0+hl_2`
`=1-0.34`
`=0.66`
`x_1=x_0+h=0+0.1=0.1`
for `n=1,x_1=0.1,y_1=0.08,z_1=0.66`
`k_1=f(x_1,y_1,z_1)`
`=f(0.1,0.08,0.66)`
`=0.66`
`l_1=g(x_1,y_1,z_1)`
`=g(0.1,0.08,0.66)`
`=-2.96`
`k_2=f(x_1+h/2,y_1+(hk_1)/2,z_1+(hl_1)/2)`
`=f(0.15,0.113,0.512)`
`=0.512`
`l_2=g(x_1+h/2,y_1+(hk_1)/2,z_1+(hl_1)/2)`
`=g(0.15,0.113,0.512)`
`=-2.5`
`y_2=y_1+hk_2`
`=0.08+0.0512`
`=0.1312`
`x_2=x_1+h=0.1+0.1=0.2`
`:.y(0.2)=0.1312`
| `n` | `x_n` | `y_n` | `z_n` | `k_1` | `l_1` | `k_2` | `l_2` | `x_(n+1)` | `y_(n+1)` | `z_(n+1)` |
| 0 | 0 | 0 | 1 | 1 | -4 | 0.8 | -3.4 | 0.1 | 0.08 | 0.66 |
| 1 | 0.1 | 0.08 | 0.66 | 0.66 | -2.96 | 0.512 | -2.5 | 0.2 | 0.1312 | |
This material is intended as a summary. Use your textbook for detail explanation.
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