1. `y=x^3+6x^2-15x+7`
Find Derivative at a Point x = 2Solution:`d/(dx)(x^3+6x^2-15x+7)`
`=d/(dx)(x^3)+d/(dx)(6x^2)-d/(dx)(15x)+d/(dx)(7)`
`=3x^2+12x-15+0`
`=3x^2+12x-15`
Now put `x=2`
`=3*2^2+12*2-15`
`=12+24-15`
`=21`
2. `y=x^3-9x^2+24x+2`
Find Derivative at a Point x = 1Solution:`=x^3-9x^2+24x+2`
`d/(dx)(x^3-9x^2+24x+2)`
`=d/(dx)(x^3)-d/(dx)(9x^2)+d/(dx)(24x)+d/(dx)(2)`
`=3x^2-18x+24+0`
`=3x^2-18x+24`
Now put `x=1`
`=3*1^2-18*1+24`
`=3-18+24`
`=9`
3. `y=4x^3+19x^2-14x+3`
Find Derivative at a Point x = 1Solution:`=4x^3+19x^2-14x+3`
`d/(dx)(4x^3+19x^2-14x+3)`
`=d/(dx)(4x^3)+d/(dx)(19x^2)-d/(dx)(14x)+d/(dx)(3)`
`=12x^2+38x-14+0`
`=12x^2+38x-14`
Now, `d^2/(dx^2)(4x^3+19x^2-14x+3)=d/(dx)(12x^2+38x-14)`
`=d/(dx)(12x^2)+d/(dx)(38x)-d/(dx)(14)`
`=24x+38-0`
`=24x+38`
Now put `x=1`
`=24*1+38`
`=24+38`
`=62`
4. `y=3x^2+12x-15`
Find Derivative at a Point x = 1Solution:`=3x^2+12x-15`
`d/(dx)(3x^2+12x-15)`
`=d/(dx)(3x^2)+d/(dx)(12x)-d/(dx)(15)`
`=6x+12-0`
`=6x+12`
Now put `x=1`
`=6*1+12`
`=6+12`
`=18`
This material is intended as a summary. Use your textbook for detail explanation.
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