7. Present value of Annuity example ( Enter your problem )
  1. Find Present value (PV) Example
  2. Find Regular Deposit (C) Example
  3. Find Interest Rate (i) Example
  4. Find Time (n) Example
Other related methods
  1. Future value using Simple Interest
  2. Future value using Compound Interest
  3. Future value of Annuity
  4. Future value of Annuity Due
  5. Present value using Simple Interest
  6. Present value using Compound Interest
  7. Present value of Annuity
  8. Present value of Annuity Due
  9. Contineous Compounding

6. Present value using Compound Interest
(Previous method)
2. Find Regular Deposit (C) Example
(Next example)

1. Find Present value (PV) Example





1. Find Present value PV = ?
Regular Deposit
(PMT Amount) C = 1000, Interest Rate i = 10%, Time n = 5 Year,
Deposit Frequency = at the end (Ordinary Annuity) of every Year (1/year)
for Present value of Annuity method


Solution:
`C=1000` (Cash flow per year)

`i=10%=0.1` per year (Interest rate)

`n=5` years (Number of periods)

Now, Present value (Ordinary Annuity) formula is
`PV_("Ordinary Annuity")=C*[(1-(1+i)^(-n))/(i)]`

`=1000*[(1-(1+0.1)^-5)/(0.1)]`

`=1000*[(1-(1.1)^-5)/(0.1)]`

`=1000*[(1-0.6209)/(0.1)]`

`=1000*3.79`

`=3790.79`

Calculating each payment present value individually and then adding them all
`1^(st)` year 1000's present value `=1000/(1.1)^1``=909.09`
`2^(nd)` year 1000's present value `=1000/(1.1)^2``=826.45`
`3^(rd)` year 1000's present value `=1000/(1.1)^3``=751.31`
`4^(th)` year 1000's present value `=1000/(1.1)^4``=683.01`
`5^(th)` year 1000's present value `=1000/(1.1)^5``=620.92`
Total present value`=3790.79`

2. Find Present value PV = ?
Regular Deposit
(PMT Amount) C = 5000, Interest Rate i = 10%, Time n = 3 Year,
Deposit Frequency = at the end (Ordinary Annuity) of every Year (1/year)
for Present value of Annuity method


Solution:
`C=5000` (Cash flow per year)

`i=10%=0.1` per year (Interest rate)

`n=3` years (Number of periods)

Now, Present value (Ordinary Annuity) formula is
`PV_("Ordinary Annuity")=C*[(1-(1+i)^(-n))/(i)]`

`=5000*[(1-(1+0.1)^-3)/(0.1)]`

`=5000*[(1-(1.1)^-3)/(0.1)]`

`=5000*[(1-0.7513)/(0.1)]`

`=5000*2.49`

`=12434.26`

Calculating each payment present value individually and then adding them all
`1^(st)` year 5000's present value `=5000/(1.1)^1``=4545.45`
`2^(nd)` year 5000's present value `=5000/(1.1)^2``=4132.23`
`3^(rd)` year 5000's present value `=5000/(1.1)^3``=3756.57`
Total present value`=12434.26`



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6. Present value using Compound Interest
(Previous method)
2. Find Regular Deposit (C) Example
(Next example)





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