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4. Future value of Annuity Due example ( Enter your problem )
  1. Find Future value (FV) Example
  2. Find Regular Deposit (C) Example
  3. Find Interest Rate (i) Example
  4. Find Time (n) Example

1. Find Future value (FV) Example





1. Find Future value FV = ?
Regular Deposit
(PMT Amount) C = 1000, Interest Rate i = 10%, Time n = 5 Year,
Deposit Frequency = at the beginning (Annuity Due) of every Year (1/year)
for Future value of Annuity Due method


Solution:
`C=1000` (Cash flow per year)

`i=10%=0.1` per year (Interest rate)

`n=5` years (Number of periods)

Now, Future value (Annuity Due) formula is
`FV_("Annuity Due")=C*[((1+i)^n-1)/(i)]*(1+i)`

`=1000*[((1+0.1)^5-1)/(0.1)]*(1+0.1)`

`=1000*[((1.1)^5-1)/(0.1)]*(1.1)`

`=1100*[((1.1)^5-1)/(0.1)]`

`=1100*[(1.6105-1)/(0.1)]`

`=1100*6.11`

`=6715.61`

Calculating each payment future value individually and then adding them all
`5^(th)` year 1000's future value in 1 year `=1000*(1.1)^1``=1100`
`4^(th)` year 1000's future value in 2 year `=1000*(1.1)^2``=1210`
`3^(rd)` year 1000's future value in 3 year `=1000*(1.1)^3``=1331`
`2^(nd)` year 1000's future value in 4 year `=1000*(1.1)^4``=1464.1`
`1^(st)` year 1000's future value in 5 year `=1000*(1.1)^5``=1610.51`
Total future value`=6715.61`

2. Find Future value FV = ?
Regular Deposit
(PMT Amount) C = 5000, Interest Rate i = 10%, Time n = 3 Year,
Deposit Frequency = at the beginning (Annuity Due) of every Year (1/year)
for Future value of Annuity Due method


Solution:
`C=5000` (Cash flow per year)

`i=10%=0.1` per year (Interest rate)

`n=3` years (Number of periods)

Now, Future value (Annuity Due) formula is
`FV_("Annuity Due")=C*[((1+i)^n-1)/(i)]*(1+i)`

`=5000*[((1+0.1)^3-1)/(0.1)]*(1+0.1)`

`=5000*[((1.1)^3-1)/(0.1)]*(1.1)`

`=5500*[((1.1)^3-1)/(0.1)]`

`=5500*[(1.331-1)/(0.1)]`

`=5500*3.31`

`=18205`

Calculating each payment future value individually and then adding them all
`3^(rd)` year 5000's future value in 1 year `=5000*(1.1)^1``=5500`
`2^(nd)` year 5000's future value in 2 year `=5000*(1.1)^2``=6050`
`1^(st)` year 5000's future value in 3 year `=5000*(1.1)^3``=6655`
Total future value`=18205`





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