1. Find Improper fraction to Mixed number of `5/3`

Solution:
`5/3=?`

Step-1: Divide the numerator 5 by the denominator 3

long division steps of `5/3`, we get quotient = 1 and remainder = 2

Solution is

1 3 5 − 3 =3 × 1   2 `:.` 5 `-:` 3=1 Remainder 2

3 table 3 × 1 = 3 3 × 2 = 6 3 × 3 = 9 3 × 4 = 12 3 × 5 = 15 3 × 6 = 18 3 × 7 = 21 3 × 8 = 24 3 × 9 = 27 3 × 10 = 30

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Step by step solution

Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.

3	5

Step-2 :
3 goes into 5 (1-times). Put a 1 in the next place of quotient and multiply 3 by 1 to get 3.
Subtract 3 from 5 to get remainder `(5-3=2)`.

	1
3	5
−	3	=3 × 1
	2

The numerator 5 divided by the denominator 3, we get quotient = 1 and remainder = 2

Step-2: The mixed number can be created by using the quotient 1 as the whole number, the remainder 2 as the numerator and the denominator 3 remains the same.
Or Step-2: Write the mixed number as quotient `("remainder")/("divisor")`

So `5/3 = 1 (2)/(3)`

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2. Find Improper fraction to Mixed number of `11/4`

Solution:
`11/4=?`

Step-1: Divide the numerator 11 by the denominator 4

long division steps of `11/4`, we get quotient = 2 and remainder = 3

Solution is

2 4 1 1   − 8 =4 × 2   3 `:.` 11 `-:` 4= 2 Remainder 3

4 table 4 × 1 = 4 4 × 2 = 8 4 × 3 = 12 4 × 4 = 16 4 × 5 = 20 4 × 6 = 24 4 × 7 = 28 4 × 8 = 32 4 × 9 = 36 4 × 10 = 40

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Step by step solution

Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.

4	1	1

Step-2 :
4 goes into 11 (2-times). Put a 2 in the next place of quotient and multiply 4 by 2 to get 8.
Subtract 8 from 11 to get remainder `(11-8=3)`.

		2
4	1	1
	−	8	=4 × 2
		3

The numerator 11 divided by the denominator 4, we get quotient = 2 and remainder = 3

Step-2: The mixed number can be created by using the quotient 2 as the whole number, the remainder 3 as the numerator and the denominator 4 remains the same.
Or Step-2: Write the mixed number as quotient `("remainder")/("divisor")`

So `11/4 = 2 (3)/(4)`

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3. Find Improper fraction to Mixed number of `19/5`

Solution:
`19/5=?`

Step-1: Divide the numerator 19 by the denominator 5

long division steps of `19/5`, we get quotient = 3 and remainder = 4

Solution is

3 5 1 9 − 1 5 =5 × 3   4 `:.` 19 `-:` 5= 3 Remainder 4

5 table 5 × 1 = 5 5 × 2 = 10 5 × 3 = 15 5 × 4 = 20 5 × 5 = 25 5 × 6 = 30 5 × 7 = 35 5 × 8 = 40 5 × 9 = 45 5 × 10 = 50

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Step by step solution

Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.

5	1	9

Step-2 :
5 goes into 19 (3-times). Put a 3 in the next place of quotient and multiply 5 by 3 to get 15.
Subtract 15 from 19 to get remainder `(19-15=4)`.

		3
5	1	9
−	1	5	=5 × 3
		4

The numerator 19 divided by the denominator 5, we get quotient = 3 and remainder = 4

Step-2: The mixed number can be created by using the quotient 3 as the whole number, the remainder 4 as the numerator and the denominator 5 remains the same.
Or Step-2: Write the mixed number as quotient `("remainder")/("divisor")`

So `19/5 = 3 (4)/(5)`

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4. Find Improper fraction to Mixed number of `10/3`

Solution:
`10/3=?`

Step-1: Divide the numerator 10 by the denominator 3

long division steps of `10/3`, we get quotient = 3 and remainder = 1

Solution is

3 3 1 0   − 9 =3 × 3   1 `:.` 10 `-:` 3= 3 Remainder 1

3 table 3 × 1 = 3 3 × 2 = 6 3 × 3 = 9 3 × 4 = 12 3 × 5 = 15 3 × 6 = 18 3 × 7 = 21 3 × 8 = 24 3 × 9 = 27 3 × 10 = 30

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Step by step solution

Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.

3	1	0

Step-2 :
3 goes into 10 (3-times). Put a 3 in the next place of quotient and multiply 3 by 3 to get 9.
Subtract 9 from 10 to get remainder `(10-9=1)`.

		3
3	1	0
	−	9	=3 × 3
		1

The numerator 10 divided by the denominator 3, we get quotient = 3 and remainder = 1

Step-2: The mixed number can be created by using the quotient 3 as the whole number, the remainder 1 as the numerator and the denominator 3 remains the same.
Or Step-2: Write the mixed number as quotient `("remainder")/("divisor")`

So `10/3 = 3 (1)/(3)`

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