We use cookies to improve your experience on our site and to show you relevant advertising. By browsing this website, you agree to our use of cookies. Learn more   

AtoZmath.com
Support us
(New) All problem can be solved using search box
I want to sell my website www.AtoZmath.com with complete code
Home What's new College Algebra Games Feedback About us
Algebra Matrix & Vector Numerical Methods Statistical Methods Operation Research Word Problems Calculus Geometry Pre-Algebra


Home > Pre-Algebra calculators > Mixed Number to Improper Fraction example
12. Mixed Number to Improper Fraction example ( Enter your problem )
( Enter your problem )
  1. Example-1
 		Other related methods
  1. Numerator and Denominator
  2. Proper and Improper Fractions
  3. Like and Unlike fractions
  4. Model Fractions (Visual Fractions)
  5. Simplify Fraction
  6. Equivalent Fractions
  7. How many eighths are equivalent to 1/2
  8. Fraction to Decimal (Mixed Number to Decimal)
  9. Decimal to Fraction (Decimal to Mixed Number)
  10. Fraction to Percentage (Mixed Number to Percentage)
  11. Improper fraction to Mixed number
  12. Mixed Number to Improper Fraction
  13. Reciprocal of a fraction
  14. LCD of fractions
  15. Convert unlike fraction to like fraction
  16. Comparing fractions
  17. Ascending and descending order of fractions
  18. Add, subtract, multiply and divide of Fractions
  19. Add, subtract, multiply and divide of Mixed numbers
  20. Visual Model for Adding, Subtracting of Fractions
  21. Simplify fraction expression
11. Improper fraction to Mixed number
(Previous method)		13. Reciprocal of a fraction
(Next method)

1. Example-1


1. Find Mixed Number to Improper Fraction of `1 2/3`

Solution:
Method-1:
`1 (2)/(3)=((1 xx 3)+2)/3=(3+2)/3=5/3`


Method-2:
`1 (2)/(3)`

Step-1 : Multiply the denominator(3) by the whole number(1)
`3 xx 1=3`

Step-2 : Add the product(3) to the numerator(2)
`3+2=5`

Step-3 :Write the sum(5) over the denominator(3)
`5/3`

So, `1 (2)/(3)=5/3`


Method-3:
`1 (2)/(3)`

Step-1 : Multiply the whole number(1) by the denominator(3)
`(1 xx 3+"[ ]")/("[ ]")`

Step-2 : Simplify
`(3+"[ ]")/("[ ]")`

Step-3 : Add the product(3) to the numerator(2)
`(3+2)/("[ ]")`

Step-4 : Simplify
`(5)/("[ ]")`

Step-5 : Write the sum(5) over the denominator(3)
`5/3`

So, `1 (2)/(3)=5/3`
2. Find Mixed Number to Improper Fraction of `2 3/4`

Solution:
Method-1:
`2 (3)/(4)=((2 xx 4)+3)/4=(8+3)/4=11/4`


Method-2:
`2 (3)/(4)`

Step-1 : Multiply the denominator(4) by the whole number(2)
`4 xx 2=8`

Step-2 : Add the product(8) to the numerator(3)
`8+3=11`

Step-3 :Write the sum(11) over the denominator(4)
`11/4`

So, `2 (3)/(4)=11/4`


Method-3:
`2 (3)/(4)`

Step-1 : Multiply the whole number(2) by the denominator(4)
`(2 xx 4+"[ ]")/("[ ]")`

Step-2 : Simplify
`(8+"[ ]")/("[ ]")`

Step-3 : Add the product(8) to the numerator(3)
`(8+3)/("[ ]")`

Step-4 : Simplify
`(11)/("[ ]")`

Step-5 : Write the sum(11) over the denominator(4)
`11/4`

So, `2 (3)/(4)=11/4`
3. Find Mixed Number to Improper Fraction of `3 4/5`

Solution:
Method-1:
`3 (4)/(5)=((3 xx 5)+4)/5=(15+4)/5=19/5`


Method-2:
`3 (4)/(5)`

Step-1 : Multiply the denominator(5) by the whole number(3)
`5 xx 3=15`

Step-2 : Add the product(15) to the numerator(4)
`15+4=19`

Step-3 :Write the sum(19) over the denominator(5)
`19/5`

So, `3 (4)/(5)=19/5`


Method-3:
`3 (4)/(5)`

Step-1 : Multiply the whole number(3) by the denominator(5)
`(3 xx 5+"[ ]")/("[ ]")`

Step-2 : Simplify
`(15+"[ ]")/("[ ]")`

Step-3 : Add the product(15) to the numerator(4)
`(15+4)/("[ ]")`

Step-4 : Simplify
`(19)/("[ ]")`

Step-5 : Write the sum(19) over the denominator(5)
`19/5`

So, `3 (4)/(5)=19/5`
4. Find Mixed Number to Improper Fraction of `1 2/7`

Solution:
Method-1:
`1 (2)/(7)=((1 xx 7)+2)/7=(7+2)/7=9/7`


Method-2:
`1 (2)/(7)`

Step-1 : Multiply the denominator(7) by the whole number(1)
`7 xx 1=7`

Step-2 : Add the product(7) to the numerator(2)
`7+2=9`

Step-3 :Write the sum(9) over the denominator(7)
`9/7`

So, `1 (2)/(7)=9/7`


Method-3:
`1 (2)/(7)`

Step-1 : Multiply the whole number(1) by the denominator(7)
`(1 xx 7+"[ ]")/("[ ]")`

Step-2 : Simplify
`(7+"[ ]")/("[ ]")`

Step-3 : Add the product(7) to the numerator(2)
`(7+2)/("[ ]")`

Step-4 : Simplify
`(9)/("[ ]")`

Step-5 : Write the sum(9) over the denominator(7)
`9/7`

So, `1 (2)/(7)=9/7`

This material is intended as a summary. Use your textbook for detail explanation.
Any bug, improvement, feedback then Submit Here


11. Improper fraction to Mixed number
(Previous method)		13. Reciprocal of a fraction
(Next method)


Share this solution or page with your friends.


Home What's new College Algebra Games Feedback About us
 
Copyright © 2024. All rights reserved. Terms, Privacy
 
 

.