1. Examples
1. Find LCD of 12/25,18/45
Solution: Step-1 : `12/25,18/45`
Step-2 : Find the least common multiple (LCM) of denominators Here, LCM of `25,45 = 225`
Step-3 : `:.` Least common denominator (LCD) of `25,45 = 225`
Step-4 : Rewriting the original inputs as equivalent fractions with the LCD: `25/225,45/225`
Steps of finding LCM of 25,45Method-1 : Finding LCM of 25,45 using Division MethodStep-1: Divide the numbers by prime factors until the remainder is 1Step-2: Multiply all the divisors to obtain the LCMLCM of `25,45=3 xx 3 xx 5 xx 5=225` Method-2 : Finding LCM of 25,45 using Prime Factorization MethodStep-1: Prime factorization of `25,45` using factor by division method Step-2: Write each number as a product of primes, matching primes vertically when possible Step-3: Bring down the primes in each column. The LCM is the product of these factors 25 | = | | | 5 | × 5 | | 45 | = | 3 | × 3 | × 5 | | |
| LCM | = | 3 | × 3 | × 5 | × 5 | = 225 |
`:.` LCM of `25,45` is `225`
2. Find LCD of 8/9,32/12,10/15
Solution: Step-1 : `8/9,32/12,10/15`
Step-2 : Find the least common multiple (LCM) of denominators Here, LCM of `9,12,15 = 180`
Step-3 : `:.` Least common denominator (LCD) of `9,12,15 = 180`
Step-4 : Rewriting the original inputs as equivalent fractions with the LCD: `9/180,12/180,15/180`
Steps of finding LCM of 9,12,15Method-1 : Finding LCM of 9,12,15 using Division MethodStep-1: Divide the numbers by prime factors until the remainder is 12 | 9 | | 12 | | 15 | 2 | 9 | | 6 | | 15 | 3 | 9 | | 3 | | 15 | 3 | 3 | | 1 | | 5 | 5 | 1 | | 1 | | 5 | | 1 | | 1 | | 1 | Step-2: Multiply all the divisors to obtain the LCMLCM of `9,12,15=2 xx 2 xx 3 xx 3 xx 5=180` Method-2 : Finding LCM of 9,12,15 using Prime Factorization MethodStep-1: Prime factorization of `9,12,15` using factor by division method Step-2: Write each number as a product of primes, matching primes vertically when possible 9 | = | | | 3 | × 3 | | | 12 | = | 2 | × 2 | × 3 | | | | 15 | = | | | 3 | | × 5 | |
Step-3: Bring down the primes in each column. The LCM is the product of these factors 9 | = | | | 3 | × 3 | | | 12 | = | 2 | × 2 | × 3 | | | | 15 | = | | | 3 | | × 5 | |
| LCM | = | 2 | × 2 | × 3 | × 3 | × 5 | = 180 |
`:.` LCM of `9,12,15` is `180`
3. Find LCD of 4/5,3/10,7/15
Solution: Step-1 : `4/5,3/10,7/15`
Step-2 : Find the least common multiple (LCM) of denominators Here, LCM of `5,10,15 = 30`
Step-3 : `:.` Least common denominator (LCD) of `5,10,15 = 30`
Step-4 : Rewriting the original inputs as equivalent fractions with the LCD: `5/30,10/30,15/30`
Steps of finding LCM of 5,10,15Method-1 : Finding LCM of 5,10,15 using Division MethodStep-1: Divide the numbers by prime factors until the remainder is 1Step-2: Multiply all the divisors to obtain the LCMLCM of `5,10,15=2 xx 3 xx 5=30` Method-2 : Finding LCM of 5,10,15 using Prime Factorization MethodStep-1: Prime factorization of `5,10,15` using factor by division method Step-2: Write each number as a product of primes, matching primes vertically when possible Step-3: Bring down the primes in each column. The LCM is the product of these factors 5 | = | | | 5 | | 10 | = | 2 | | × 5 | | 15 | = | | 3 | × 5 | |
| LCM | = | 2 | × 3 | × 5 | = 30 |
`:.` LCM of `5,10,15` is `30`
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