Find index number using Fixed base method by taking base year 2008, Chain base method, Fixed base method by taking average of years 2010,2011
Year | Price |
2008 | 230 |
2009 | 250 |
2010 | 230 |
2011 | 250 |
2012 | 270 |
2013 | 280 |
2014 | 300 |
2015 | 300 |
Solution:
1. Fixed base method :
`"Index Number I"=("Price of current year")/("Price of base year") xx 100`
We will find the fixed base index number by taking 2008 as base year
Base Price = 230 for base year 2008
The index number will be taken as 100 for the price 230 in the base year 2008
2. Chain base method :
`"Index Number I"=("Price of current year")/("Price of preceding year") xx 100`
Price for the year 2008 is not given here.
Hence, we will take the index number for 2008 as 100.
3. Fixed base method by taking average of years :
Average price for year `2010,2011` `=(230+250)/2=240`
`"Index Number I"=("Price of current year")/("Average base price") xx 100`
Year | Price | Fixed base index number base year `2008`
`=("Price of current year")/("Price of base year") xx 100` | Chain base index number
`=("Price of current year")/("Price of preceding year") xx 100` | Index number by taking average of price in year `2010,2011`
`=(230+250)/2=240` as base year price |
2008 | 230 | `230/230 xx 100=100` | `230/230 xx 100=100` | `230/240 xx 100=95.83` |
2009 | 250 | `250/230 xx 100=108.7` | `250/230 xx 100=108.7` | `250/240 xx 100=104.17` |
2010 | 230 | `230/230 xx 100=100` | `230/250 xx 100=92` | `230/240 xx 100=95.83` |
2011 | 250 | `250/230 xx 100=108.7` | `250/230 xx 100=108.7` | `250/240 xx 100=104.17` |
2012 | 270 | `270/230 xx 100=117.39` | `270/250 xx 100=108` | `270/240 xx 100=112.5` |
2013 | 280 | `280/230 xx 100=121.74` | `280/270 xx 100=103.7` | `280/240 xx 100=116.67` |
2014 | 300 | `300/230 xx 100=130.43` | `300/280 xx 100=107.14` | `300/240 xx 100=125` |
2015 | 300 | `300/230 xx 100=130.43` | `300/300 xx 100=100` | `300/240 xx 100=125` |
This material is intended as a summary. Use your textbook for detail explanation.
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