1. Find Walsh's index number

Item	Price0	Quantity0	Price1	Quantity1
Rice	39	1	40	1.5
Milk	40	12	44	10
Bread	45	2	50	1.5
Banana	30	2	36	1.5

Solution:

Item	`p_0`	`q_0`	`p_1`	`q_1`	`q_w=sqrt(q_0xxq_1)`	`p_0q_w`	`p_1q_w`
Rice	39	1	40	1.5	1.2247	47.765	48.9898
Milk	40	12	44	10	10.9545	438.178	481.9959
Bread	45	2	50	1.5	1.7321	77.9423	86.6025
Banana	30	2	36	1.5	1.7321	51.9615	62.3538
---	---	---	---	---	---	---	---
Total						`615.8469`	`679.942`

1. By Walsh's Method, price index number

`I_W=(sum p_1q_w)/(sum p_0q_w) xx 100`

`=(679.942)/(615.8469) xx 100`

`=110.41`

Thus, there is a rise of `(110.41-100)=10.41%` in prices

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2. Find Walsh's index number

Item	Price0	Quantity0	Price1	Quantity1
A	10	20	12	22
B	8	16	8	18
C	5	10	6	11
D	4	7	4	8

Solution:

Item	`p_0`	`q_0`	`p_1`	`q_1`	`q_w=sqrt(q_0xxq_1)`	`p_0q_w`	`p_1q_w`
A	10	20	12	22	20.9762	209.7618	251.7141
B	8	16	8	18	16.9706	135.7645	135.7645
C	5	10	6	11	10.4881	52.4404	62.9285
D	4	7	4	8	7.4833	29.9333	29.9333
---	---	---	---	---	---	---	---
Total						`427.9`	`480.3404`

1. By Walsh's Method, price index number

`I_W=(sum p_1q_w)/(sum p_0q_w) xx 100`

`=(480.3404)/(427.9) xx 100`

`=112.26`

Thus, there is a rise of `(112.26-100)=12.26%` in prices

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3. Find Walsh's index number

Item	Price0	Quantity0	Price1	Quantity1
A	3	25	5	28
B	1	50	3	60
C	2	30	1	30
D	5	15	6	12

Solution:

Item	`p_0`	`q_0`	`p_1`	`q_1`	`q_w=sqrt(q_0xxq_1)`	`p_0q_w`	`p_1q_w`
A	3	25	5	28	26.4575	79.3725	132.2876
B	1	50	3	60	54.7723	54.7723	164.3168
C	2	30	1	30	30	60	30
D	5	15	6	12	13.4164	67.082	80.4984
---	---	---	---	---	---	---	---
Total						`261.2268`	`407.1028`

1. By Walsh's Method, price index number

`I_W=(sum p_1q_w)/(sum p_0q_w) xx 100`

`=(407.1028)/(261.2268) xx 100`

`=155.84`

Thus, there is a rise of `(155.84-100)=55.84%` in prices

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