1. Find antilog(1), base=10
Solution:
`x=antilog_(b)(y)=b^(y)`
`antilog_(10)(1)=(10)^(1)=10`
2. Find antilog(1), base=5
Solution:
`x=antilog_(b)(y)=b^(y)`
`antilog_(5)(1)=(5)^(1)=5`
3. Find antilog(1), base=e
Solution:
`x=antilog_(b)(y)=b^(y)`
`antilog_(e)(1)=(e)^(1)=2.7182818285`
This material is intended as a summary. Use your textbook for detail explanation.
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