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21. determinants using properties of determinants example ( Enter your problem )
  1. Example `[[201,210,220],[151,155,140],[50,55,80]]`
  2. Example `[[100,205,105],[200,408,207],[300,608,310]]`
  3. Example `[[2,1970,1978],[5,1960,1980],[7,1950,1978]]`
  4. Example `[[1977,1979,1981],[1940,1943,1946],[10,17,24]]`
Other related methods
  1. Transforming matrix to Row Echelon Form
  2. Transforming matrix to Reduced Row Echelon Form
  3. Rank of matrix
  4. Characteristic polynomial of matrix
  5. Eigenvalues
  6. Eigenvectors (Eigenspace)
  7. Triangular Matrix
  8. LU decomposition using Gauss Elimination method of matrix
  9. LU decomposition using Doolittle's method of matrix
  10. LU decomposition using Crout's method of matrix
  11. Diagonal Matrix
  12. Cholesky Decomposition
  13. QR Decomposition (Gram Schmidt Method)
  14. QR Decomposition (Householder Method)
  15. LQ Decomposition
  16. Pivots
  17. Singular Value Decomposition (SVD)
  18. Moore-Penrose Pseudoinverse
  19. Power Method for dominant eigenvalue
  20. determinants using Sarrus Rule
  21. determinants using properties of determinants
  22. Row Space
  23. Column Space
  24. Null Space

3. Example `[[2,1970,1978],[5,1960,1980],[7,1950,1978]]`
(Previous example)
22. Row Space
(Next method)

4. Example `[[1977,1979,1981],[1940,1943,1946],[10,17,24]]`





Find value of determinant using properties of determinants ...
`[[1977,1979,1981],[1940,1943,1946],[10,17,24]]`


Solution:
 `A=` 
 1977  1979  1981 
 1940  1943  1946 
 10  17  24 


Now, `C_2=C_2 - C_1` and `C_3=C_3 - C_2`

 `=` 
 1977  2  2 
 1940  3  3 
 10  7  7 


Here `C_2=C_3`, So value of the determinant is 0

`=0`

Method-2: Determinant by expanding cofactors

`|A|` = 
 `1977`  `1979`  `1981` 
 `1940`  `1943`  `1946` 
 `10`  `17`  `24` 


 =
 `1977` × 
 `1943`  `1946` 
 `17`  `24` 
 `-1979` × 
 `1940`  `1946` 
 `10`  `24` 
 `+1981` × 
 `1940`  `1943` 
 `10`  `17` 


`=1977 xx (1943 × 24 - 1946 × 17) -1979 xx (1940 × 24 - 1946 × 10) +1981 xx (1940 × 17 - 1943 × 10)`

`=1977 xx (46632 -33082) -1979 xx (46560 -19460) +1981 xx (32980 -19430)`

`=1977 xx (13550) -1979 xx (27100) +1981 xx (13550)`

`= 26788350 -53630900 +26842550`

`=0`




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3. Example `[[2,1970,1978],[5,1960,1980],[7,1950,1978]]`
(Previous example)
22. Row Space
(Next method)





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