1. find multiples of 1 using repeated addition method

Solution:
Multiples of 1 by performing Repeated addition method

		1	=	1
1	`+`	1	=	2
2	`+`	1	=	3
3	`+`	1	=	4
4	`+`	1	=	5
5	`+`	1	=	6
6	`+`	1	=	7
7	`+`	1	=	8
8	`+`	1	=	9
9	`+`	1	=	10

Multiples of 1 are `1,2,3,4,5,6,7,8,9,10,...`

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2. find multiples of 2 using repeated addition method

Solution:
Multiples of 2 by performing Repeated addition method

		2	=	2
2	`+`	2	=	4
4	`+`	2	=	6
6	`+`	2	=	8
8	`+`	2	=	10
10	`+`	2	=	12
12	`+`	2	=	14
14	`+`	2	=	16
16	`+`	2	=	18
18	`+`	2	=	20

Multiples of 2 are `2,4,6,8,10,12,14,16,18,20,...`

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3. find multiples of 3 using repeated addition method

Solution:
Multiples of 3 by performing Repeated addition method

		3	=	3
3	`+`	3	=	6
6	`+`	3	=	9
9	`+`	3	=	12
12	`+`	3	=	15
15	`+`	3	=	18
18	`+`	3	=	21
21	`+`	3	=	24
24	`+`	3	=	27
27	`+`	3	=	30

Multiples of 3 are `3,6,9,12,15,18,21,24,27,30,...`

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4. find multiples of 4 using repeated addition method

Solution:
Multiples of 4 by performing Repeated addition method

		4	=	4
4	`+`	4	=	8
8	`+`	4	=	12
12	`+`	4	=	16
16	`+`	4	=	20
20	`+`	4	=	24
24	`+`	4	=	28
28	`+`	4	=	32
32	`+`	4	=	36
36	`+`	4	=	40

Multiples of 4 are `4,8,12,16,20,24,28,32,36,40,...`

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5. find multiples of 5 using repeated addition method

Solution:
Multiples of 5 by performing Repeated addition method

		5	=	5
5	`+`	5	=	10
10	`+`	5	=	15
15	`+`	5	=	20
20	`+`	5	=	25
25	`+`	5	=	30
30	`+`	5	=	35
35	`+`	5	=	40
40	`+`	5	=	45
45	`+`	5	=	50

Multiples of 5 are `5,10,15,20,25,30,35,40,45,50,...`

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6. find multiples of 6 using repeated addition method

Solution:
Multiples of 6 by performing Repeated addition method

		6	=	6
6	`+`	6	=	12
12	`+`	6	=	18
18	`+`	6	=	24
24	`+`	6	=	30
30	`+`	6	=	36
36	`+`	6	=	42
42	`+`	6	=	48
48	`+`	6	=	54
54	`+`	6	=	60

Multiples of 6 are `6,12,18,24,30,36,42,48,54,60,...`

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7. find multiples of 7 using repeated addition method

Solution:
Multiples of 7 by performing Repeated addition method

		7	=	7
7	`+`	7	=	14
14	`+`	7	=	21
21	`+`	7	=	28
28	`+`	7	=	35
35	`+`	7	=	42
42	`+`	7	=	49
49	`+`	7	=	56
56	`+`	7	=	63
63	`+`	7	=	70

Multiples of 7 are `7,14,21,28,35,42,49,56,63,70,...`

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8. find multiples of 8 using repeated addition method

Solution:
Multiples of 8 by performing Repeated addition method

		8	=	8
8	`+`	8	=	16
16	`+`	8	=	24
24	`+`	8	=	32
32	`+`	8	=	40
40	`+`	8	=	48
48	`+`	8	=	56
56	`+`	8	=	64
64	`+`	8	=	72
72	`+`	8	=	80

Multiples of 8 are `8,16,24,32,40,48,56,64,72,80,...`

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9. find multiples of 9 using repeated addition method

Solution:
Multiples of 9 by performing Repeated addition method

		9	=	9
9	`+`	9	=	18
18	`+`	9	=	27
27	`+`	9	=	36
36	`+`	9	=	45
45	`+`	9	=	54
54	`+`	9	=	63
63	`+`	9	=	72
72	`+`	9	=	81
81	`+`	9	=	90

Multiples of 9 are `9,18,27,36,45,54,63,72,81,90,...`

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10. find multiples of 10 using repeated addition method

Solution:
Multiples of 10 by performing Repeated addition method

		10	=	10
10	`+`	10	=	20
20	`+`	10	=	30
30	`+`	10	=	40
40	`+`	10	=	50
50	`+`	10	=	60
60	`+`	10	=	70
70	`+`	10	=	80
80	`+`	10	=	90
90	`+`	10	=	100

Multiples of 10 are `10,20,30,40,50,60,70,80,90,100,...`

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11. find multiples of 11 using repeated addition method

Solution:
Multiples of 11 by performing Repeated addition method

		11	=	11
11	`+`	11	=	22
22	`+`	11	=	33
33	`+`	11	=	44
44	`+`	11	=	55
55	`+`	11	=	66
66	`+`	11	=	77
77	`+`	11	=	88
88	`+`	11	=	99
99	`+`	11	=	110

Multiples of 11 are `11,22,33,44,55,66,77,88,99,110,...`

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12. find multiples of 12 using repeated addition method

Solution:
Multiples of 12 by performing Repeated addition method

		12	=	12
12	`+`	12	=	24
24	`+`	12	=	36
36	`+`	12	=	48
48	`+`	12	=	60
60	`+`	12	=	72
72	`+`	12	=	84
84	`+`	12	=	96
96	`+`	12	=	108
108	`+`	12	=	120

Multiples of 12 are `12,24,36,48,60,72,84,96,108,120,...`

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13. find multiples of 13 using repeated addition method

Solution:
Multiples of 13 by performing Repeated addition method

		13	=	13
13	`+`	13	=	26
26	`+`	13	=	39
39	`+`	13	=	52
52	`+`	13	=	65
65	`+`	13	=	78
78	`+`	13	=	91
91	`+`	13	=	104
104	`+`	13	=	117
117	`+`	13	=	130

Multiples of 13 are `13,26,39,52,65,78,91,104,117,130,...`

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14. find multiples of 14 using repeated addition method

Solution:
Multiples of 14 by performing Repeated addition method

		14	=	14
14	`+`	14	=	28
28	`+`	14	=	42
42	`+`	14	=	56
56	`+`	14	=	70
70	`+`	14	=	84
84	`+`	14	=	98
98	`+`	14	=	112
112	`+`	14	=	126
126	`+`	14	=	140

Multiples of 14 are `14,28,42,56,70,84,98,112,126,140,...`

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15. find multiples of 15 using repeated addition method

Solution:
Multiples of 15 by performing Repeated addition method

		15	=	15
15	`+`	15	=	30
30	`+`	15	=	45
45	`+`	15	=	60
60	`+`	15	=	75
75	`+`	15	=	90
90	`+`	15	=	105
105	`+`	15	=	120
120	`+`	15	=	135
135	`+`	15	=	150

Multiples of 15 are `15,30,45,60,75,90,105,120,135,150,...`

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16. find multiples of 16 using repeated addition method

Solution:
Multiples of 16 by performing Repeated addition method

		16	=	16
16	`+`	16	=	32
32	`+`	16	=	48
48	`+`	16	=	64
64	`+`	16	=	80
80	`+`	16	=	96
96	`+`	16	=	112
112	`+`	16	=	128
128	`+`	16	=	144
144	`+`	16	=	160

Multiples of 16 are `16,32,48,64,80,96,112,128,144,160,...`

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17. find multiples of 17 using repeated addition method

Solution:
Multiples of 17 by performing Repeated addition method

		17	=	17
17	`+`	17	=	34
34	`+`	17	=	51
51	`+`	17	=	68
68	`+`	17	=	85
85	`+`	17	=	102
102	`+`	17	=	119
119	`+`	17	=	136
136	`+`	17	=	153
153	`+`	17	=	170

Multiples of 17 are `17,34,51,68,85,102,119,136,153,170,...`

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18. find multiples of 18 using repeated addition method

Solution:
Multiples of 18 by performing Repeated addition method

		18	=	18
18	`+`	18	=	36
36	`+`	18	=	54
54	`+`	18	=	72
72	`+`	18	=	90
90	`+`	18	=	108
108	`+`	18	=	126
126	`+`	18	=	144
144	`+`	18	=	162
162	`+`	18	=	180

Multiples of 18 are `18,36,54,72,90,108,126,144,162,180,...`

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19. find multiples of 19 using repeated addition method

Solution:
Multiples of 19 by performing Repeated addition method

		19	=	19
19	`+`	19	=	38
38	`+`	19	=	57
57	`+`	19	=	76
76	`+`	19	=	95
95	`+`	19	=	114
114	`+`	19	=	133
133	`+`	19	=	152
152	`+`	19	=	171
171	`+`	19	=	190

Multiples of 19 are `19,38,57,76,95,114,133,152,171,190,...`

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20. find multiples of 20 using repeated addition method

Solution:
Multiples of 20 by performing Repeated addition method

		20	=	20
20	`+`	20	=	40
40	`+`	20	=	60
60	`+`	20	=	80
80	`+`	20	=	100
100	`+`	20	=	120
120	`+`	20	=	140
140	`+`	20	=	160
160	`+`	20	=	180
180	`+`	20	=	200

Multiples of 20 are `20,40,60,80,100,120,140,160,180,200,...`

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21. find multiples of 21 using repeated addition method

Solution:
Multiples of 21 by performing Repeated addition method

		21	=	21
21	`+`	21	=	42
42	`+`	21	=	63
63	`+`	21	=	84
84	`+`	21	=	105
105	`+`	21	=	126
126	`+`	21	=	147
147	`+`	21	=	168
168	`+`	21	=	189
189	`+`	21	=	210

Multiples of 21 are `21,42,63,84,105,126,147,168,189,210,...`

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22. find multiples of 22 using repeated addition method

Solution:
Multiples of 22 by performing Repeated addition method

		22	=	22
22	`+`	22	=	44
44	`+`	22	=	66
66	`+`	22	=	88
88	`+`	22	=	110
110	`+`	22	=	132
132	`+`	22	=	154
154	`+`	22	=	176
176	`+`	22	=	198
198	`+`	22	=	220

Multiples of 22 are `22,44,66,88,110,132,154,176,198,220,...`

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23. find multiples of 23 using repeated addition method

Solution:
Multiples of 23 by performing Repeated addition method

		23	=	23
23	`+`	23	=	46
46	`+`	23	=	69
69	`+`	23	=	92
92	`+`	23	=	115
115	`+`	23	=	138
138	`+`	23	=	161
161	`+`	23	=	184
184	`+`	23	=	207
207	`+`	23	=	230

Multiples of 23 are `23,46,69,92,115,138,161,184,207,230,...`

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24. find multiples of 24 using repeated addition method

Solution:
Multiples of 24 by performing Repeated addition method

		24	=	24
24	`+`	24	=	48
48	`+`	24	=	72
72	`+`	24	=	96
96	`+`	24	=	120
120	`+`	24	=	144
144	`+`	24	=	168
168	`+`	24	=	192
192	`+`	24	=	216
216	`+`	24	=	240

Multiples of 24 are `24,48,72,96,120,144,168,192,216,240,...`

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25. find multiples of 25 using repeated addition method

Solution:
Multiples of 25 by performing Repeated addition method

		25	=	25
25	`+`	25	=	50
50	`+`	25	=	75
75	`+`	25	=	100
100	`+`	25	=	125
125	`+`	25	=	150
150	`+`	25	=	175
175	`+`	25	=	200
200	`+`	25	=	225
225	`+`	25	=	250

Multiples of 25 are `25,50,75,100,125,150,175,200,225,250,...`

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26. find multiples of 26 using repeated addition method

Solution:
Multiples of 26 by performing Repeated addition method

		26	=	26
26	`+`	26	=	52
52	`+`	26	=	78
78	`+`	26	=	104
104	`+`	26	=	130
130	`+`	26	=	156
156	`+`	26	=	182
182	`+`	26	=	208
208	`+`	26	=	234
234	`+`	26	=	260

Multiples of 26 are `26,52,78,104,130,156,182,208,234,260,...`

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27. find multiples of 27 using repeated addition method

Solution:
Multiples of 27 by performing Repeated addition method

		27	=	27
27	`+`	27	=	54
54	`+`	27	=	81
81	`+`	27	=	108
108	`+`	27	=	135
135	`+`	27	=	162
162	`+`	27	=	189
189	`+`	27	=	216
216	`+`	27	=	243
243	`+`	27	=	270

Multiples of 27 are `27,54,81,108,135,162,189,216,243,270,...`

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28. find multiples of 28 using repeated addition method

Solution:
Multiples of 28 by performing Repeated addition method

		28	=	28
28	`+`	28	=	56
56	`+`	28	=	84
84	`+`	28	=	112
112	`+`	28	=	140
140	`+`	28	=	168
168	`+`	28	=	196
196	`+`	28	=	224
224	`+`	28	=	252
252	`+`	28	=	280

Multiples of 28 are `28,56,84,112,140,168,196,224,252,280,...`

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29. find multiples of 29 using repeated addition method

Solution:
Multiples of 29 by performing Repeated addition method

		29	=	29
29	`+`	29	=	58
58	`+`	29	=	87
87	`+`	29	=	116
116	`+`	29	=	145
145	`+`	29	=	174
174	`+`	29	=	203
203	`+`	29	=	232
232	`+`	29	=	261
261	`+`	29	=	290

Multiples of 29 are `29,58,87,116,145,174,203,232,261,290,...`

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30. find multiples of 30 using repeated addition method

Solution:
Multiples of 30 by performing Repeated addition method

		30	=	30
30	`+`	30	=	60
60	`+`	30	=	90
90	`+`	30	=	120
120	`+`	30	=	150
150	`+`	30	=	180
180	`+`	30	=	210
210	`+`	30	=	240
240	`+`	30	=	270
270	`+`	30	=	300

Multiples of 30 are `30,60,90,120,150,180,210,240,270,300,...`

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