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2. Find Multiple of 8 using Repeated addition method example ( Enter your problem )
  1. Example-1
Other related methods
  1. Find Multiple of 8 using Multiplication method
  2. Find Multiple of 8 using Repeated addition method
  3. Find the first 6 Multiple of 8
  4. Find the sum of first 12 Multiple of 12
  5. Find the average of first 12 Multiple of 12
  6. Find Multiple of 7 that are less than or equal to 56
  7. Find Multiple of 12 that are between 20 and 70
  8. Find the smallest Multiple of 13 greater than 1000
  9. Find the largest Multiple of 7 less than 1000
  10. How many Multiple of 7 between 100 and 1000
  11. Is 104 a multiple of 8

1. Find Multiple of 8 using Multiplication method
(Previous method)
3. Find the first 6 Multiple of 8
(Next method)

1. Example-1





1. find multiples of 1 using repeated addition method

Solution:
Multiples of 1 by performing Repeated addition method
1 = 1
1`+`1 = 2
2`+`1 = 3
3`+`1 = 4
4`+`1 = 5
5`+`1 = 6
6`+`1 = 7
7`+`1 = 8
8`+`1 = 9
9`+`1 = 10


Multiples of 1 are `1,2,3,4,5,6,7,8,9,10,...`
2. find multiples of 2 using repeated addition method

Solution:
Multiples of 2 by performing Repeated addition method
2 = 2
2`+`2 = 4
4`+`2 = 6
6`+`2 = 8
8`+`2 = 10
10`+`2 = 12
12`+`2 = 14
14`+`2 = 16
16`+`2 = 18
18`+`2 = 20


Multiples of 2 are `2,4,6,8,10,12,14,16,18,20,...`
3. find multiples of 3 using repeated addition method

Solution:
Multiples of 3 by performing Repeated addition method
3 = 3
3`+`3 = 6
6`+`3 = 9
9`+`3 = 12
12`+`3 = 15
15`+`3 = 18
18`+`3 = 21
21`+`3 = 24
24`+`3 = 27
27`+`3 = 30


Multiples of 3 are `3,6,9,12,15,18,21,24,27,30,...`
4. find multiples of 4 using repeated addition method

Solution:
Multiples of 4 by performing Repeated addition method
4 = 4
4`+`4 = 8
8`+`4 = 12
12`+`4 = 16
16`+`4 = 20
20`+`4 = 24
24`+`4 = 28
28`+`4 = 32
32`+`4 = 36
36`+`4 = 40


Multiples of 4 are `4,8,12,16,20,24,28,32,36,40,...`
5. find multiples of 5 using repeated addition method

Solution:
Multiples of 5 by performing Repeated addition method
5 = 5
5`+`5 = 10
10`+`5 = 15
15`+`5 = 20
20`+`5 = 25
25`+`5 = 30
30`+`5 = 35
35`+`5 = 40
40`+`5 = 45
45`+`5 = 50


Multiples of 5 are `5,10,15,20,25,30,35,40,45,50,...`
6. find multiples of 6 using repeated addition method

Solution:
Multiples of 6 by performing Repeated addition method
6 = 6
6`+`6 = 12
12`+`6 = 18
18`+`6 = 24
24`+`6 = 30
30`+`6 = 36
36`+`6 = 42
42`+`6 = 48
48`+`6 = 54
54`+`6 = 60


Multiples of 6 are `6,12,18,24,30,36,42,48,54,60,...`
7. find multiples of 7 using repeated addition method

Solution:
Multiples of 7 by performing Repeated addition method
7 = 7
7`+`7 = 14
14`+`7 = 21
21`+`7 = 28
28`+`7 = 35
35`+`7 = 42
42`+`7 = 49
49`+`7 = 56
56`+`7 = 63
63`+`7 = 70


Multiples of 7 are `7,14,21,28,35,42,49,56,63,70,...`
8. find multiples of 8 using repeated addition method

Solution:
Multiples of 8 by performing Repeated addition method
8 = 8
8`+`8 = 16
16`+`8 = 24
24`+`8 = 32
32`+`8 = 40
40`+`8 = 48
48`+`8 = 56
56`+`8 = 64
64`+`8 = 72
72`+`8 = 80


Multiples of 8 are `8,16,24,32,40,48,56,64,72,80,...`
9. find multiples of 9 using repeated addition method

Solution:
Multiples of 9 by performing Repeated addition method
9 = 9
9`+`9 = 18
18`+`9 = 27
27`+`9 = 36
36`+`9 = 45
45`+`9 = 54
54`+`9 = 63
63`+`9 = 72
72`+`9 = 81
81`+`9 = 90


Multiples of 9 are `9,18,27,36,45,54,63,72,81,90,...`
10. find multiples of 10 using repeated addition method

Solution:
Multiples of 10 by performing Repeated addition method
10 = 10
10`+`10 = 20
20`+`10 = 30
30`+`10 = 40
40`+`10 = 50
50`+`10 = 60
60`+`10 = 70
70`+`10 = 80
80`+`10 = 90
90`+`10 = 100


Multiples of 10 are `10,20,30,40,50,60,70,80,90,100,...`
11. find multiples of 11 using repeated addition method

Solution:
Multiples of 11 by performing Repeated addition method
11 = 11
11`+`11 = 22
22`+`11 = 33
33`+`11 = 44
44`+`11 = 55
55`+`11 = 66
66`+`11 = 77
77`+`11 = 88
88`+`11 = 99
99`+`11 = 110


Multiples of 11 are `11,22,33,44,55,66,77,88,99,110,...`
12. find multiples of 12 using repeated addition method

Solution:
Multiples of 12 by performing Repeated addition method
12 = 12
12`+`12 = 24
24`+`12 = 36
36`+`12 = 48
48`+`12 = 60
60`+`12 = 72
72`+`12 = 84
84`+`12 = 96
96`+`12 = 108
108`+`12 = 120


Multiples of 12 are `12,24,36,48,60,72,84,96,108,120,...`
13. find multiples of 13 using repeated addition method

Solution:
Multiples of 13 by performing Repeated addition method
13 = 13
13`+`13 = 26
26`+`13 = 39
39`+`13 = 52
52`+`13 = 65
65`+`13 = 78
78`+`13 = 91
91`+`13 = 104
104`+`13 = 117
117`+`13 = 130


Multiples of 13 are `13,26,39,52,65,78,91,104,117,130,...`
14. find multiples of 14 using repeated addition method

Solution:
Multiples of 14 by performing Repeated addition method
14 = 14
14`+`14 = 28
28`+`14 = 42
42`+`14 = 56
56`+`14 = 70
70`+`14 = 84
84`+`14 = 98
98`+`14 = 112
112`+`14 = 126
126`+`14 = 140


Multiples of 14 are `14,28,42,56,70,84,98,112,126,140,...`
15. find multiples of 15 using repeated addition method

Solution:
Multiples of 15 by performing Repeated addition method
15 = 15
15`+`15 = 30
30`+`15 = 45
45`+`15 = 60
60`+`15 = 75
75`+`15 = 90
90`+`15 = 105
105`+`15 = 120
120`+`15 = 135
135`+`15 = 150


Multiples of 15 are `15,30,45,60,75,90,105,120,135,150,...`
16. find multiples of 16 using repeated addition method

Solution:
Multiples of 16 by performing Repeated addition method
16 = 16
16`+`16 = 32
32`+`16 = 48
48`+`16 = 64
64`+`16 = 80
80`+`16 = 96
96`+`16 = 112
112`+`16 = 128
128`+`16 = 144
144`+`16 = 160


Multiples of 16 are `16,32,48,64,80,96,112,128,144,160,...`
17. find multiples of 17 using repeated addition method

Solution:
Multiples of 17 by performing Repeated addition method
17 = 17
17`+`17 = 34
34`+`17 = 51
51`+`17 = 68
68`+`17 = 85
85`+`17 = 102
102`+`17 = 119
119`+`17 = 136
136`+`17 = 153
153`+`17 = 170


Multiples of 17 are `17,34,51,68,85,102,119,136,153,170,...`
18. find multiples of 18 using repeated addition method

Solution:
Multiples of 18 by performing Repeated addition method
18 = 18
18`+`18 = 36
36`+`18 = 54
54`+`18 = 72
72`+`18 = 90
90`+`18 = 108
108`+`18 = 126
126`+`18 = 144
144`+`18 = 162
162`+`18 = 180


Multiples of 18 are `18,36,54,72,90,108,126,144,162,180,...`
19. find multiples of 19 using repeated addition method

Solution:
Multiples of 19 by performing Repeated addition method
19 = 19
19`+`19 = 38
38`+`19 = 57
57`+`19 = 76
76`+`19 = 95
95`+`19 = 114
114`+`19 = 133
133`+`19 = 152
152`+`19 = 171
171`+`19 = 190


Multiples of 19 are `19,38,57,76,95,114,133,152,171,190,...`
20. find multiples of 20 using repeated addition method

Solution:
Multiples of 20 by performing Repeated addition method
20 = 20
20`+`20 = 40
40`+`20 = 60
60`+`20 = 80
80`+`20 = 100
100`+`20 = 120
120`+`20 = 140
140`+`20 = 160
160`+`20 = 180
180`+`20 = 200


Multiples of 20 are `20,40,60,80,100,120,140,160,180,200,...`
21. find multiples of 21 using repeated addition method

Solution:
Multiples of 21 by performing Repeated addition method
21 = 21
21`+`21 = 42
42`+`21 = 63
63`+`21 = 84
84`+`21 = 105
105`+`21 = 126
126`+`21 = 147
147`+`21 = 168
168`+`21 = 189
189`+`21 = 210


Multiples of 21 are `21,42,63,84,105,126,147,168,189,210,...`
22. find multiples of 22 using repeated addition method

Solution:
Multiples of 22 by performing Repeated addition method
22 = 22
22`+`22 = 44
44`+`22 = 66
66`+`22 = 88
88`+`22 = 110
110`+`22 = 132
132`+`22 = 154
154`+`22 = 176
176`+`22 = 198
198`+`22 = 220


Multiples of 22 are `22,44,66,88,110,132,154,176,198,220,...`
23. find multiples of 23 using repeated addition method

Solution:
Multiples of 23 by performing Repeated addition method
23 = 23
23`+`23 = 46
46`+`23 = 69
69`+`23 = 92
92`+`23 = 115
115`+`23 = 138
138`+`23 = 161
161`+`23 = 184
184`+`23 = 207
207`+`23 = 230


Multiples of 23 are `23,46,69,92,115,138,161,184,207,230,...`
24. find multiples of 24 using repeated addition method

Solution:
Multiples of 24 by performing Repeated addition method
24 = 24
24`+`24 = 48
48`+`24 = 72
72`+`24 = 96
96`+`24 = 120
120`+`24 = 144
144`+`24 = 168
168`+`24 = 192
192`+`24 = 216
216`+`24 = 240


Multiples of 24 are `24,48,72,96,120,144,168,192,216,240,...`
25. find multiples of 25 using repeated addition method

Solution:
Multiples of 25 by performing Repeated addition method
25 = 25
25`+`25 = 50
50`+`25 = 75
75`+`25 = 100
100`+`25 = 125
125`+`25 = 150
150`+`25 = 175
175`+`25 = 200
200`+`25 = 225
225`+`25 = 250


Multiples of 25 are `25,50,75,100,125,150,175,200,225,250,...`
26. find multiples of 26 using repeated addition method

Solution:
Multiples of 26 by performing Repeated addition method
26 = 26
26`+`26 = 52
52`+`26 = 78
78`+`26 = 104
104`+`26 = 130
130`+`26 = 156
156`+`26 = 182
182`+`26 = 208
208`+`26 = 234
234`+`26 = 260


Multiples of 26 are `26,52,78,104,130,156,182,208,234,260,...`
27. find multiples of 27 using repeated addition method

Solution:
Multiples of 27 by performing Repeated addition method
27 = 27
27`+`27 = 54
54`+`27 = 81
81`+`27 = 108
108`+`27 = 135
135`+`27 = 162
162`+`27 = 189
189`+`27 = 216
216`+`27 = 243
243`+`27 = 270


Multiples of 27 are `27,54,81,108,135,162,189,216,243,270,...`
28. find multiples of 28 using repeated addition method

Solution:
Multiples of 28 by performing Repeated addition method
28 = 28
28`+`28 = 56
56`+`28 = 84
84`+`28 = 112
112`+`28 = 140
140`+`28 = 168
168`+`28 = 196
196`+`28 = 224
224`+`28 = 252
252`+`28 = 280


Multiples of 28 are `28,56,84,112,140,168,196,224,252,280,...`
29. find multiples of 29 using repeated addition method

Solution:
Multiples of 29 by performing Repeated addition method
29 = 29
29`+`29 = 58
58`+`29 = 87
87`+`29 = 116
116`+`29 = 145
145`+`29 = 174
174`+`29 = 203
203`+`29 = 232
232`+`29 = 261
261`+`29 = 290


Multiples of 29 are `29,58,87,116,145,174,203,232,261,290,...`
30. find multiples of 30 using repeated addition method

Solution:
Multiples of 30 by performing Repeated addition method
30 = 30
30`+`30 = 60
60`+`30 = 90
90`+`30 = 120
120`+`30 = 150
150`+`30 = 180
180`+`30 = 210
210`+`30 = 240
240`+`30 = 270
270`+`30 = 300


Multiples of 30 are `30,60,90,120,150,180,210,240,270,300,...`


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1. Find Multiple of 8 using Multiplication method
(Previous method)
3. Find the first 6 Multiple of 8
(Next method)





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