Binary Division Example ( Enter your problem )
  1. Addition
  2. Subtraction
  3. Multiplication
  4. Division

4. Binary Division





1. Find division of `(1011)_2` and `(10)_2`

Solution:

Solution is
  101
101011
10  =10 × 1
  1 
  0 =10 × 0
  11
  10=10 × 1
  1

`:.` 1011 `-:` 10= 101 Remainder 1
10 table
10×1=10
10×10=100




Step by step solution

Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.
     
101011

Step-2 :
10 goes into 10 (1-times). Put a 1 in the next place of quotient and multiply 10 by 1 to get 10.
Subtract 10 from 10 to get remainder `(10-10=0)`.


  1  
101011
10  =10 × 1
  0  

Step-3 :
Now, bring down 1 from the dividend, to make 1
  1  
101011
10  =10 × 1
  1 

Step-4 :
10 goes into 1 (0-times). Put a 0 in the next place of quotient and multiply 10 by 0 to get 0.
Subtract 0 from 1 to get remainder `(1-0=1)`.


  10 
101011
10  =10 × 1
  1 
  0 =10 × 0
  1 

Step-5 :
Now, bring down 1 from the dividend, to make 11
  10 
101011
10  =10 × 1
  1 
  0 =10 × 0
  11

Step-6 :
10 goes into 11 (1-times). Put a 1 in the next place of quotient and multiply 10 by 1 to get 10.
Subtract 10 from 11 to get remainder `(11-10=1)`.


  101
101011
10  =10 × 1
  1 
  0 =10 × 0
  11
  10=10 × 1
  1


2. Find division of `(11101)_2` and `(101)_2`

Solution:

Solution is
  101
10111101
101  =101 × 1
  100 
  0 =101 × 0
  1001
  101=101 × 1
  100

`:.` 11101 `-:` 101= 101 Remainder 100
101 table
101×1=101
101×10=1010




Step by step solution

Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.
      
10111101

Step-2 :
101 goes into 111 (1-times). Put a 1 in the next place of quotient and multiply 101 by 1 to get 101.
Subtract 101 from 111 to get remainder `(111-101=10)`.


  1  
10111101
101  =101 × 1
  10  

Step-3 :
Now, bring down 0 from the dividend, to make 100
  1  
10111101
101  =101 × 1
  100 

Step-4 :
101 goes into 100 (0-times). Put a 0 in the next place of quotient and multiply 101 by 0 to get 0.
Subtract 0 from 100 to get remainder `(100-0=100)`.


  10 
10111101
101  =101 × 1
  100 
  0 =101 × 0
  100 

Step-5 :
Now, bring down 1 from the dividend, to make 1001
  10 
10111101
101  =101 × 1
  100 
  0 =101 × 0
  1001

Step-6 :
101 goes into 1001 (1-times). Put a 1 in the next place of quotient and multiply 101 by 1 to get 101.
Subtract 101 from 1001 to get remainder `(1001-101=100)`.


  101
10111101
101  =101 × 1
  100 
  0 =101 × 0
  1001
  101=101 × 1
  100


3. Find division of `(11101)_2` and `(110)_2`

Solution:

Solution is
  100
11011101
110  =110 × 1
  10 
  0 =110 × 0
  101
  0=110 × 0
  101

`:.` 11101 `-:` 110= 100 Remainder 101
110 table
110×1=110
110×10=1100




Step by step solution

Step by step solution :
Step-1 :
Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.
      
11011101

Step-2 :
110 goes into 111 (1-times). Put a 1 in the next place of quotient and multiply 110 by 1 to get 110.
Subtract 110 from 111 to get remainder `(111-110=1)`.


  1  
11011101
110  =110 × 1
  1  

Step-3 :
Now, bring down 0 from the dividend, to make 10
  1  
11011101
110  =110 × 1
  10 

Step-4 :
110 goes into 10 (0-times). Put a 0 in the next place of quotient and multiply 110 by 0 to get 0.
Subtract 0 from 10 to get remainder `(10-0=10)`.


  10 
11011101
110  =110 × 1
  10 
  0 =110 × 0
  10 

Step-5 :
Now, bring down 1 from the dividend, to make 101
  10 
11011101
110  =110 × 1
  10 
  0 =110 × 0
  101

Step-6 :
110 goes into 101 (0-times). Put a 0 in the next place of quotient and multiply 110 by 0 to get 0.
Subtract 0 from 101 to get remainder `(101-0=101)`.


  100
11011101
110  =110 × 1
  10 
  0 =110 × 0
  101
  0=110 × 0
  101





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