Step by step solution :Step-1 :Set up the problem with long division bracket. Put dividend inside bracket and divisor on outside left.
Step-2 :101 goes into 111 (1-times). Put a 1 in the next place of quotient and multiply 101 by 1 to get 101.
Subtract 101 from 111 to get remainder `(111-101=10)`.
| | | | 1 | | |
| 101 | 1 | 1 | 1 | 0 | 1 |
| − | 1 | 0 | 1 | | | =101 × 1 |
| | | 1 | 0 | | | |
Step-3 :Now, bring down 0 from the dividend, to make 100
| | | | 1 | | |
| 101 | 1 | 1 | 1 | 0 | 1 |
| − | 1 | 0 | 1 | | | =101 × 1 |
| | | 1 | 0 | 0 | | |
Step-4 :101 goes into 100 (0-times). Put a 0 in the next place of quotient and multiply 101 by 0 to get 0.
Subtract 0 from 100 to get remainder `(100-0=100)`.
| | | | 1 | 0 | |
| 101 | 1 | 1 | 1 | 0 | 1 |
| − | 1 | 0 | 1 | | | =101 × 1 |
| | | 1 | 0 | 0 | | |
| | | | − | 0 | | =101 × 0 |
| | | 1 | 0 | 0 | | |
Step-5 :Now, bring down 1 from the dividend, to make 1001
| | | | 1 | 0 | |
| 101 | 1 | 1 | 1 | 0 | 1 |
| − | 1 | 0 | 1 | | | =101 × 1 |
| | | 1 | 0 | 0 | | |
| | | | − | 0 | | =101 × 0 |
| | | 1 | 0 | 0 | 1 | |
Step-6 :101 goes into 1001 (1-times). Put a 1 in the next place of quotient and multiply 101 by 1 to get 101.
Subtract 101 from 1001 to get remainder `(1001-101=100)`.
| | | | 1 | 0 | 1 |
| 101 | 1 | 1 | 1 | 0 | 1 |
| − | 1 | 0 | 1 | | | =101 × 1 |
| | | 1 | 0 | 0 | | |
| | | | − | 0 | | =101 × 0 |
| | | 1 | 0 | 0 | 1 | |
| | | − | 1 | 0 | 1 | =101 × 1 |
| | | | 1 | 0 | 0 | |