6. Previous 2 or 3 terms addition, multiplicaiton series
1. Find next 3 numbers in the sequence `0,1,1,2,3,5,8`
Each number in the series is the sum of preceding 2 numbers
`0+1=1`
`1+1=2`
`1+2=3`
`2+3=5`
`3+5=8`
So required number are
`5+8=13`
`8+13=21`
`13+21=34`
`:.` The next 3 number for given series `0,1,1,2,3,5,8` are `13,21,34`
Solution-1
2. Find next 3 numbers in the sequence `1,2,3,5,8`
Each number in the series is the sum of preceding 2 numbers
`1+2=3`
`2+3=5`
`3+5=8`
So required number are
`5+8=13`
`8+13=21`
`13+21=34`
`:.` The next 3 number for given series `1,2,3,5,8` are `13,21,34`
Solution-1
3. Find next 3 numbers in the sequence `1,1,2,4,8`
Each number in the series is the sum of preceding all numbers
`1+1=2`
`1+1+2=4`
`1+1+2+4=8`
So required number are
`1+1+2+4+8=16`
`1+1+2+4+8+16=32`
`1+1+2+4+8+16+32=64`
`:.` The next 3 number for given series `1,1,2,4,8` are `16,32,64`
Solution-1
4. Find next 3 numbers in the sequence `4,5,20,100`
Each number in the series is the multiplication of preceding 2 numbers
`4xx5=20`
`5xx20=100`
So required number are
`20xx100=2000`
`100xx2000=200000`
`2000xx200000=400000000`
`:.` The next 3 number for given series `4,5,20,100` are `2000,200000,400000000`
Solution-1
This material is intended as a summary. Use your textbook for detail explanation.
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