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6. Quadratic Equation - Roots for non-zero denominator example ( Enter your problem )
  1. Example-1 : `(5x-18)/(x+2)=(2x-6)/(x-1)`
  2. Example-2 : `(x)/(x+1)+(x+1)/(x)=5/2`
  3. Example-3 : `4((4x+1)/(4x-1))^(2)+(4x+1)/(4x-1)=3`
  4. Example-4 : `(4x+1)/(4x-1)+(4x-1)/(4x+1)=3`

1. Example-1 : `(5x-18)/(x+2)=(2x-6)/(x-1)`





1. Find roots of the equation `(5x-18)/(x+2) = (2x-6)/(x-1)`

` (5x-18)/(x+2) = (2x-6)/(x-1)`

` => (5x-18)*(x-1) = (2x-6)*(x+2)`

` => 5x^2-23x+18 = 2x^2-2x-12`

` => 3x^2-21x+30 = 0`

` => (3x^2-21x+30) = 0`

` => 3x^2-21x+30 = 0`

` => 3(x^2-7x+10) = 0`

` => 3(x^2-2x-5x+10) = 0`

` => 3(x(x-2)+(-5)(x-2)) = 0`

` => 3(x-5)(x-2) = 0`

` => (x-5) = 0" or "(x-2) = 0`

` => x = 5" or "x = 2`






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