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Mode using Grouping Method Example-4 ( Enter your problem )
  1. Formula
  2. Example-1
  3. Example-2
  4. Example-3
  5. Example-4
  6. Example-5
  7. Example-6
Other related methods
  1. Mean, Median and Mode
  2. Quartile
  3. Decile
  4. Percentile
  5. Octile
  6. Quintile
  7. Population Variance, Standard deviation and coefficient of variation
  8. Sample Variance, Standard deviation and coefficient of variation
  9. Population Skewness, Kurtosis
  10. Sample Skewness, Kurtosis
  11. Geometric mean, Harmonic mean
  12. Mean deviation, Coefficient of Mean deviation
  13. Quartile deviation, Coefficient of QD, Interquartile range
  14. Decile deviation, Coefficient of DD, Interdecile range
  15. Percentile deviation, Coefficient of PD, Interpercentile range
  16. Five number summary
  17. Box and Whisker Plots
  18. Mode using Grouping Method
  19. Less than type Cumulative frequency table
  20. More than type Cumulative frequency table
  21. Class and their frequency table

4. Example-3
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6. Example-5
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5. Example-4





Calculate Mode using Grouping Method from the following grouped data
ClassFrequency
10 - 204
20 - 306
30 - 405
40 - 5010
50 - 6020
60 - 7022
70 - 8024
80 - 906
90 - 1003


Solution:
Mode using Grouping Method :
1) In column-I, write the original frequency
2) In column-II, combine the frequency two by two, starting from top
3) In column-III, combine the frequency two by two, starting from second
4) In column-IV, combine the frequency three by three, starting from top
5) In column-V, combine the frequency three by three, starting from second
6) In column-VI, combine the frequency three by three, starting from third

Grouping Table :
ClassI
Frequency
II
(1+2)
III
(2+3)
IV
(1+2+3)
V
(2+3+4)
VI
(3+4+5)
10-204
4+6=10
20-3064+6+5=15
6+5=11
30-4056+5+10=21
5+10=15
40-50105+10+20=35
10+20=30
50-602010+20+22=52
20+22=42
60-702220+22+24=66
22+24=46
70-802422+24+6=52
24+6=30
80-90624+6+3=33
6+3=9
90-1003

1) 24 is the maximum value in the column-I and it is an individual frequency of Class 70-80. Therefore, we have tick(✓) this Class.
2) 42 is the maximum value in the column-II and it is the sum of 20 and 22; i.e., of Class 50-60 and 60-70. Therefore, we have tick(✓) this both Class.
3) 46 is the maximum value in the column-III and it is the sum of 22 and 24; i.e., of Class 60-70 and 70-80. Therefore, we have tick(✓) this both Class.
4) 52 is the maximum value in the column-IV and it is the sum of 10, 20, and 22; i.e, of Class 40-50, 50-60 and 60-70. Therefore, we have tick(✓) this three Class.
5) 66 is the maximum value in the column-V and it is the sum of 20, 22, and 24; i.e, of Class 50-60, 60-70 and 70-80. Therefore, we have tick(✓) this three Class.
6) 52 is the maximum value in the column-VI and it is the sum of 22, 24, and 6; i.e, of Class 60-70, 70-80 and 80-90. Therefore, we have tick(✓) this three Class.

Analysis Table :
ColumnIIIIIIIVVVITotal
Max Frequency244246526652
10-20-
20-30-
30-40-
40-501
50-603
60-705
70-804
80-901
90-100-

Since 60-70 has the maximum ticks 5. So mode class is 60-70.
`:.` The mode class is `60 - 70`.

`:. L = `lower boundary point of mode class `=60`

`:. f_1 = ` frequency of the mode class `=22`

`:. f_0 = ` frequency of the preceding class `=20`

`:. f_2 = ` frequency of the succedding class `=24`

`:. c = ` class length of mode class `=10`

`Z=L+(|f_1-f_0|)/(|f_1-f_0|+|f_1-f_2|) * c`

`=60+(|22-20|)/(|22-20| + |22-24|) * 10`

`=60+2/4 * 10`

`=60+5`

`=65`




This material is intended as a summary. Use your textbook for detail explanation.
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