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Mean Example for ungrouped data ( Enter your problem )
  1. Formula & Example
  2. Mean Example
  3. Median Example
  4. Mode Example

2. Mean Example





Measures of central tendency


There are 3 common measures of central tendency
1. Mean
2. Median
3. Mode
Mean :
The mean (or average) of number of observations is the sum of the values of observations divided by the total number of observations.
It is denoted by `bar x` and read as x bar.

So if `x_1,x_2,...,x_n` are n observations, then mean is

`bar x=(x_1+x_2+...+x_n)/n=(sum x)/n`

Here greek symbol `sum` (sigma) is used for summation.

1. Find the Mean of `3,13,11,15,5,4,2`

Solution:
Mean `bar x=(sum x)/n`

`=(3+13+11+15+5+4+2)/7`

`=53/7`

`=7.5714`


2. Find the Mean of `10,50,30,20,10,20,70,30`

Solution:
Mean `bar x=(sum x)/n`

`=(10+50+30+20+10+20+70+30)/8`

`=240/8`

`=30`


3. Find the Mean of `69,66,67,69,64,63,65,68,72`

Solution:
Mean `bar x=(sum x)/n`

`=(69+66+67+69+64+63+65+68+72)/9`

`=603/9`

`=67`


If values of observations are large, then to simplify calculation, Assume any number A and subtract it from all the observations.
Then mean is `bar x=A+(sum d_i)/n`, where `d_i=x_i-A`

4. Find the Mean of `69,66,67,69,64,63,65,68,72`

Solution:
x`d=x-A=x-65`
694
661
672
69 4
64-1
63-2
650
683
727
------
`n=9``sum d=18`

`bar x=A+(sum d_i)/n`
`=65+18/9`
`=65+2`
`=67`





This material is intended as a summary. Use your textbook for detail explanation.
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