|
Construct a grouped frequency distribution table Example-1
( Enter your problem )
|
- Example-1
|
Other related methods
- Mean, Median and Mode
- Quartile, Decile, Percentile, Octile, Quintile
- Population Variance, Standard deviation and coefficient of variation
- Sample Variance, Standard deviation and coefficient of variation
- Population Skewness, Kurtosis
- Sample Skewness, Kurtosis
- Geometric mean, Harmonic mean
- Mean deviation, Quartile deviation, Decile deviation, Percentile deviation
- Five number summary
- Box and Whisker Plots
- Construct an ungrouped frequency distribution table
- Construct a grouped frequency distribution table
- Maximum, Minimum
- Sum, Length
- Range, Mid Range
- Stem and leaf plot
- Ascending order, Descending order
|
|
1. Example-1
1. Construct a grouped frequency distribution table from the following data
`77,41,85,82,85,96,93,66,78,94,50,57`
Solution:
`77,41,85,82,85,96,93,66,78,94,50,57`
Here minimum value is 41 and maximum value is 96
| Class | Class Boundaries | Tally marks | Frequency | | 41 - 50 | | | | | 51 - 60 | | | | | 61 - 70 | | | | | 71 - 80 | | | | | 81 - 90 | | | | | 91 - 100 | | | | | Total | | | |
Class boundaries : subtracting 0.5 from lower class limit and adding 0.5 to upper class limit
| Class | Class Boundaries | Tally marks | Frequency | | 41 - 50 | 40.5 - 50.5 | | | | 51 - 60 | 50.5 - 60.5 | | | | 61 - 70 | 60.5 - 70.5 | | | | 71 - 80 | 70.5 - 80.5 | | | | 81 - 90 | 80.5 - 90.5 | | | | 91 - 100 | 90.5 - 100.5 | | | | Total | | | |
For each value draw a tally mark, next to the class in which this value exists.
`77,41,85,82,85,96,93,66,78,94,50,57`
| Class | Class Boundaries | Tally marks | Frequency | | 41 - 50 | 40.5 - 50.5 | || | | | 51 - 60 | 50.5 - 60.5 | | | | | 61 - 70 | 60.5 - 70.5 | | | | | 71 - 80 | 70.5 - 80.5 | || | | | 81 - 90 | 80.5 - 90.5 | ||| | | | 91 - 100 | 90.5 - 100.5 | ||| | | | Total | | | |
Count tally marks to determine the total frequency of each class.
| Class | Class Boundaries | Tally marks | Frequency | | 41 - 50 | 40.5 - 50.5 | || | 2 | | 51 - 60 | 50.5 - 60.5 | | | 1 | | 61 - 70 | 60.5 - 70.5 | | | 1 | | 71 - 80 | 70.5 - 80.5 | || | 2 | | 81 - 90 | 80.5 - 90.5 | ||| | 3 | | 91 - 100 | 90.5 - 100.5 | ||| | 3 | | Total | | | 12 |
2. Construct a grouped frequency distribution table from the following data
`85,96,76,108,85,80,100,85,70,95`
Solution:
`85,96,76,108,85,80,100,85,70,95`
Here minimum value is 70 and maximum value is 108
| Class | Class Boundaries | Tally marks | Frequency | | 61 - 70 | | | | | 71 - 80 | | | | | 81 - 90 | | | | | 91 - 100 | | | | | 101 - 110 | | | | | Total | | | |
Class boundaries : subtracting 0.5 from lower class limit and adding 0.5 to upper class limit
| Class | Class Boundaries | Tally marks | Frequency | | 61 - 70 | 60.5 - 70.5 | | | | 71 - 80 | 70.5 - 80.5 | | | | 81 - 90 | 80.5 - 90.5 | | | | 91 - 100 | 90.5 - 100.5 | | | | 101 - 110 | 100.5 - 110.5 | | | | Total | | | |
For each value draw a tally mark, next to the class in which this value exists.
`85,96,76,108,85,80,100,85,70,95`
| Class | Class Boundaries | Tally marks | Frequency | | 61 - 70 | 60.5 - 70.5 | | | | | 71 - 80 | 70.5 - 80.5 | || | | | 81 - 90 | 80.5 - 90.5 | ||| | | | 91 - 100 | 90.5 - 100.5 | ||| | | | 101 - 110 | 100.5 - 110.5 | | | | | Total | | | |
Count tally marks to determine the total frequency of each class.
| Class | Class Boundaries | Tally marks | Frequency | | 61 - 70 | 60.5 - 70.5 | | | 1 | | 71 - 80 | 70.5 - 80.5 | || | 2 | | 81 - 90 | 80.5 - 90.5 | ||| | 3 | | 91 - 100 | 90.5 - 100.5 | ||| | 3 | | 101 - 110 | 100.5 - 110.5 | | | 1 | | Total | | | 10 |
This material is intended as a summary. Use your textbook for detail explanation.
Any bug, improvement, feedback then
|
|
|
