1. Find Collinear vectors
`A=(3,4,5)`, `B=(6,8,10)`Solution:Here `vec A=(3,4,5),vec B=(6,8,10)`
Two vectors are collinear if relations of their coordinates are equal.
`(A_1)/(B_1)=(3)/(6)=1/2`
`(A_2)/(B_2)=(4)/(8)=1/2`
`(A_3)/(B_3)=(5)/(10)=1/2`
Since `(A_1)/(B_1)=(A_2)/(B_2)=(A_3)/(B_3)`, So vectors are collinear.
2. Find Collinear vectors
`A=(3,4)`, `B=(6,8)`Solution:Here `vec A=(3,4),vec B=(6,8)`
Two vectors are collinear if relations of their coordinates are equal.
`(A_1)/(B_1)=(3)/(6)=1/2`
`(A_2)/(B_2)=(4)/(8)=1/2`
Since `(A_1)/(B_1)=(A_2)/(B_2)`, So vectors are collinear.
3. Find Collinear vectors
`A=(3,4,0)`, `B=(2,2,1)`Solution:Here `vec A=(3,4,0),vec B=(2,2,1)`
Two vectors `vec A` and `vec B` are collinear if there exists a number n such that `vec B = n * vec A`
Find the first nonzero coefficient of vector `vec A`
`A_1=3`
`n=B_1/A_1=2/3=2/3`
`2/3 * vec A`
`=(2/3*A_1,2/3*A_2,2/3*A_3)`
`=(2/3*3,2/3*4,2/3*0)`
`=(2,8/3,0)`
`!=vec B`
Since `vec B != 2/3 * vec A`, so vectors are not collinear.
This material is intended as a summary. Use your textbook for detail explanation.
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