2. Example-2
1. Find 3×A A=(5,-1,1)Solution:Here →A=(5,-1,1),→B=(-2,3,4),→C=(5,-1,1)3⋅→A=3⋅(A1,A2,A3)=(3⋅A1,3⋅A2,3⋅A3)=(3⋅5,3⋅(-1),3⋅1)=(15,-3,3)
2. Find 2×B B=(-2,3,4)Solution:Here →A=(5,-1,1),→B=(-2,3,4),→C=(5,-1,1)2⋅→B=2⋅(B1,B2,B3)=(2⋅B1,2⋅B2,2⋅B3)=(2⋅(-2),2⋅3,2⋅4)=(-4,6,8)
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