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Home > Numerical methods calculators > Numerical Interpolation using Newton's Divided Difference Interpolation formula calculator
Method and examples
Numerical interpolation using Newton's Divided Difference Interpolation formula
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Method  
Type your data in either horizontal or verical format,
for seperator you can use '-' or ',' or ';' or space or tab
for sample click random button

OR
Rows :  
Click On Generate
x =
Option :
  1. X300304305307
    f(x)2.47712.48292.48432.4871
    and x=301
  2. X22.53
    f(x)0.693150.916291.09861
    and x=2.7
  3. X0134
    f(x)-1201224
    and x=5
  4. X-10367
    f(x)3-6398221611
    and x=8
  5. X0.20.30.50.70.8
    f(x)1.1486981.2311441.4142141.6245051.741101
    and x=0.40
f(x) =
x1 = and x2 =
 x =
Step value (h) =  OR  Inverval (N) =
=
Option :
  1. `f(x)=2x^3-4x+1`
    x1 = 2 and x2 = 4
    x = 3.8
    Step value (h) = 1
    or N = 5
  2. `f(x)=2x^3-4x+1`
    x1 = 2 and x2 = 4
    x = 2.1
    Step value (h) = 1
    or N = 8
  3. `f(x)=x^3-x+1`
    x1 = 2 and x2 = 4
    x = 3.8
    Step value (h) = 1
    or N = 5
  4. `f(x)=x^3-x+1`
    x1 = 2 and x2 = 4
    x = 2.1
    Step value (h) = 1
    or N = 8
  5. `f(x)=x^3+x+2`
    x1 = 2 and x2 = 4
    x = 3.8
    Step value (h) = 1
    or N = 5
  6. `f(x)=x^3+x+2`
    x1 = 2 and x2 = 4
    x = 2.1
    Step value (h) = 1
    or N = 8
  7. `f(x)=sin(x)`
    x1 = 0 and x2 = 1.57
    x = 2
    Step value (h) = 1
    or N = 8
  8. `f(x)=cos(x)`
    x1 = 0 and x2 = 1.57
    x = 2
    Step value (h) = 1
    or N = 8
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