We use cookies to improve your experience on our site and to show you relevant advertising.
By browsing this website, you agree to our use of cookies. Learn
more

2. For arithemetic progression addition of 3 terms is 27 and their multiplication is 648, then that nos.

3. Find the sum of all natural nos between 100 to 200 and which are not divisible by 4.

4. For arithemetic progression, addition of three terms is 51 and multiplication of end terms is 273, then find that nos.

5. For arithemetic progression, addition of 4 terms is 4 and addition of multiplication of end terms and multiplication of middle terms is -38, then find that nos.

2. The interest on a certain amount of money at 8% per year for a period of 4 years is Rs 512. Find the sum of money.

3. A sum of money lent at simple interest amounts to Rs 1596 in 3/2 years and to 1860 in 5/2 years. Find the sum & the rate of interest.

4. A sum was put at simple interest at a certain rate for 2 years. Had it been put at 3 % highere rate, it whould have fetched Rs. 300 more. Find the sum.

5. A shopkeeper borrowed Rs. 20000 from two money lenders. For one loan he paid 12% and for the other 14% per annum. After one year, he paid Rs. 2560 as interest. How much did he borrow at each rate ?

6. At what rate percent per annum will sum of money double in 8 years?

7. Rajeev deposited money in the post office which is doubled in 20 years at a simple rate of interest. In how many years will the original sum triple itself?

Cash Price = 440 Down Payemnt = 200 Remaining Balance = 440 - 200 = 240 The installment to be paid at the end of 1 months = 244 Therefore the interest charged on Rs 240, for a period of 1 months = Rs 244 - Rs 240 = 4 If R % is the rate of interest per annum, then (240 × R × 1) / (100 × 12) = 4 R = 20 Thus, the rate of interest charged under the installment plan is = 20 per annum

2. A washing machine is available at Rs 6400 cash or for Rs 1400 cash down payment and 5 monthly installments of Rs 1030 each. Calculate the rate of interest charged under the instalment plan.

3. A computer is sold by a company for Rs 19200 cash or for Rs 4800 cash down payment together with 5 equal monthly installments. If the rate of interest charged by the company is 12% per annum, find each installment.

4. A man borrows money from a finance company and has to pay it back in 2 equal half yearly installments of Rs 4945 each. If the interest is charged by the finance company at the rate of 15 % per annum compounded as installment plan, find the principal and the total interest paid.

5. Ram borrowed a sum of money and returned it in 3 equal quarterly installments of Rs 17576 each. Find the sum borrowed, if the rate of interest charged was 16 % per annum compounded as installment plan. Find also the total interest charged.

2. A's annual income is increased from Rs 60000 to Rs 75000 . Find the percentage of increase in A's income.

3. In a school of 225 boys, 15 were absent then what percent were present ?

4. A earns 25 % more than B. By what percent does B earn less then A.

5. A reduction of 20 % in the price of basmati rice would enable a man to buy 2 kg of rice more for Rs 250. Find the reduced price per kg.

6. Find the selling price of an item, of which the printed price is Rs 25000 if the successive discounts given are 10 %, 8 % and 4 %.

7. The successive discount of 10 % and 5 % are given on the purchased Computer. If the final price of the Computer is Rs 10260, then find the printed price of the Computer.

1. The mean of 10 observations is 12.5 . While calculating the mean
one observation was by mistake taken as (-8) instead of (+8) . Find the correct
mean.
Here Mean X = 12.5
and n=10
`Sigma`(X) = X × n = 12.5 × 10 = 125
`:.` the correct sum `Sigma`(X) = 125 - (Wrong Observation) + (Correct Observation)
= 125 - (-8) + (8) = 141 .
`:.` correct mean = ^{correct
sum} / _{n} = ^{141} /
_{10} = 14.1

2. The sum of 15 observation is 343 . If we remove two
observation 18 and 26 , then find out the mean of remaining
observations.

Here `Sigma`(X) = 343 and n= 15
If we remove two observation then 13 observation left.
Sum of 13 observation `Sigma`(X') = 343 - ( ( 18 ) + ( 26 ) ) = 299 Then the mean of remaining 13 observations = ^{`Sigma`(X')} / _{ n } = ^{ 299 } / _{ 13 }= 23.
and many more...