Numerical interpolation using Stirling's formula calculator

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Home > Numerical methods calculators > Numerical Interpolation using Stirling's formula calculator

Method and examples

Numerical interpolation using Stirling's formula

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Method

Type your data in either horizontal or verical format,
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for sample click random button

Rows :

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x =

Option :

X 20 25 30 35 40
f(x) 49225 48316 47236 45926 44306
and x=28
X 10 11 12 13 14
f(x) 0.23967 0.28060 0.31788 0.35209 0.38368
and x=12.2
X 0 5 10 15 20 25 30
f(x) 0 0.0875 0.1763 0.2679 0.3640 0.4663 0.5774
and x=16

f(x) =

x₁ = and x₂ =

x =

Option :

`f(x)=2x^3-4x+1`
x1 = 2 and x2 = 4
x = 3.8
Step value (h) = 1
or N = 5
`f(x)=2x^3-4x+1`
x1 = 2 and x2 = 4
x = 2.1
Step value (h) = 1
or N = 8
`f(x)=x^3-x+1`
x1 = 2 and x2 = 4
x = 3.8
Step value (h) = 1
or N = 5
`f(x)=x^3-x+1`
x1 = 2 and x2 = 4
x = 2.1
Step value (h) = 1
or N = 8
`f(x)=x^3+x+2`
x1 = 2 and x2 = 4
x = 3.8
Step value (h) = 1
or N = 5
`f(x)=x^3+x+2`
x1 = 2 and x2 = 4
x = 2.1
Step value (h) = 1
or N = 8
`f(x)=sin(x)`
x1 = 0 and x2 = 1.57
x = 2
Step value (h) = 1
or N = 8
`f(x)=cos(x)`
x1 = 0 and x2 = 1.57
x = 2
Step value (h) = 1
or N = 8

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