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Problem: 10 years ago, A was 4 times as old as B. 10 years hence, A will be 2 times as old as B. At present, A's age and B's age is ? [ Calculator, Method and examples ]

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Your problem `->` 10 years ago, A was 4 times as old as B. 10 years hence, A will be 2 times as old as B. At present, A's age and B's age is ?


10 years ago, A was `4` times as old as B. (given)

Let 10 years ago B.'s age = `x`. Then, 10 years ago A's age = `4x`.

10 years hence, A will be `2` times as old as B. (given)

10 years hence, their ages be `4x+20` and `x+20`

`:.4x+20=2(x+20)`

`:.4x+20=2x+40`

`:.4x-2x=40-20`

`:.2x=20`

`:.x=10`

`:.` A's present age`=4x+10=50` years and B.'s present age`=x+10=20` years








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