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 Problem: 10 years ago, A was 4 times as old as B. 10 years hence, A will be 2 times as old as B. At present, A's age and B's age is ? [ Calculator, Method and examples ]Solution:Your problem -> 10 years ago, A was 4 times as old as B. 10 years hence, A will be 2 times as old as B. At present, A's age and B's age is ?10 years ago, A was 4 times as old as B. (given)Let 10 years ago B.'s age = x. Then, 10 years ago A's age = 4x.10 years hence, A will be 2 times as old as B. (given)10 years hence, their ages be 4x+20 and x+20:.4x+20=2(x+20):.4x+20=2x+40:.4x-2x=40-20:.2x=20:.x=10:. A's present age=4x+10=50 years and B.'s present age=x+10=20 years

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