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Find A=[[1,2],[3,4]],A^3

Solution:
Your problem `->` A=[[1,2],[3,4]],A^3


`A^2`=`A×A`=
`1``2`
`3``4`
×
`1``2`
`3``4`


=
`1×1+2×3``1×2+2×4`
`3×1+4×3``3×2+4×4`


=
`1+6``2+8`
`3+12``6+16`


=
`7``10`
`15``22`


`A^3`=`A^2×A`=
`7``10`
`15``22`
×
`1``2`
`3``4`


=
`37×1+54×3``37×2+54×4`
`81×1+118×3``81×2+118×4`


=
`37+162``74+216`
`81+354``162+472`


=
`37``54`
`81``118`


`A^3` = 
`1``2`
`3``4`
3
 = 
`37``54`
`81``118`







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