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Find Addition subtraction 7y+2x=11,3x-y=5

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Your problem `->` Addition subtraction 7y+2x=11,3x-y=5


`7y+2x=11`

`:.2x+7y=11`

and ` 3x-y=5`

`:.3x-y=5`

`=>2x+7y=11 ->(i)`

`=>3x-y=5 ->(ii)`

Adding Equation `(i)` and `(ii)`, we get

`=>5x+6y=16`

`=>5x+6y=16 ->(iii)` (On simplifying)

Subtracting Equation `(ii)` from `(i)`, we get

`=>-x+8y=6`

`=>x-8y=-6 ->(iv)` (On simplifying)

Now solving these equations `(iii)` and `(iv)` using substitution method

Suppose,
`5x+6y=16 ->(1)`

and `x-8y=-6 ->(2)`

Taking equation `(2)`, we have

`x-8y=-6`

`=>x=8y-6 ->(3)`

Putting `x=8y-6` in equation `(1)`, we get

`5x+6y=16`

`=>5(8y-6)+6y=16`

`=>40y-30+6y=16`

`=>46y-30=16`

`=>46y=16+30`

`=>46y=46`

`=>y=1 ->(4)`

Now, Putting `y=1` in equation `(3)`, we get

`x=8y-6`

`=>x=8(1)-6`

`=>x=8-6`

`=>x=2`

`:. x=2" and "y=1`






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