Home

Solve any problem
(step by step solutions)
Input table (Matrix, Statistics)
Mode :
SolutionHelp
Solution
Problem: Area of triangle (3,4,0),(2,2,1) [ Calculator, Method and examples ]

Solution:
Your problem `->` Area of triangle (3,4,0),(2,2,1)


Here `vec A=(3,4,0),vec B=(2,2,1)`

The angle between two vectors `vec A` and `vec B` is given by

`cos(theta)=(vec A * vec B)/(|vec A| * |vec B|)`

1. Calculate dot product
`vec A * vec B`

`=A_1*B_1 + A_2*B_2 + A_3*B_3`

`=3*2 + 4*2 + 0*1`

`=6 + 8 + 0`

`=14`

2. Calculate magnitude of vectors
`|vec A|`

`=sqrt(A_1^2 + A_2^2 + A_3^2)`

`=sqrt(3^2 + 4^2 + 0^2)`

`=sqrt(9 + 16 + 0)`

`=sqrt(25)`

`=5`


`|vec B|`

`=sqrt(B_1^2 + B_2^2 + B_3^2)`

`=sqrt(2^2 + 2^2 + 1^2)`

`=sqrt(4 + 4 + 1)`

`=sqrt(9)`

`=3`


3. Calculate angle between vectors
`cos(theta)=(14)/(5 * 3)=14/15`

`:. theta=cos^(-1)(14/15)=0.3672` rad

`:. theta=21.0395 ^circ`






Solution provided by AtoZmath.com
Any wrong solution, solution improvement, feedback then Submit Here
Want to know about AtoZmath.com and me
  
 

 
Copyright © 2019. All rights reserved. Terms, Privacy





We use cookies to improve your experience on our site and to show you relevant advertising. By browsing this website, you agree to our use of cookies. Learn more