Home

Solve any problem
(step by step solutions)
Input table (Matrix, Statistics)
Mode :
SolutionHelp
Solution
For arithemetic progression f( 17 ) = 6 , then find S( 33 ).

Solution:
Your problem `->` For arithemetic progression f( 17 ) = 6 , then find S( 33 ).


We have given `f(17) = 6` and we have to find `S_33 = ?`

We know that, `f(n) = a + (n - 1)d`

`f(17) = a + (17 - 1)d`

`=> a + 16d = 6 ->(1)`


We know that, `S_n = n/2 [2a + (n - 1)d]`

`S_33 = 33/2 * [2a + (33 - 1)d]`

`=> S_33 = 33 * [a + 16 d]`

`=> S_33 = 33 * 6` (Using (1))

`=> S_33 = 198`






Solution provided by AtoZmath.com
Any wrong solution, solution improvement, feedback then Submit Here
Want to know about AtoZmath.com and me
  
 

Share with your friends
 
Copyright © 2018. All rights reserved. Terms, Privacy