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 Solution For arithemetic progression f( 17 ) = 6 , then find S( 33 ).Solution:Your problem -> For arithemetic progression f( 17 ) = 6 , then find S( 33 ).We have given f(17) = 6 and we have to find S_33 = ?We know that, f(n) = a + (n - 1)df(17) = a + (17 - 1)d=> a + 16d = 6 ->(1)We know that, S_n = n/2 [2a + (n - 1)d]S_33 = 33/2 * [2a + (33 - 1)d]=> S_33 = 33 * [a + 16 d]=> S_33 = 33 * 6 (Using (1))=> S_33 = 198 Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me