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For geometric progression addition of 3 terms is 26 and their multiplication is 216 , then that numbers

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Your problem `->` For geometric progression addition of 3 terms is 26 and their multiplication is 216 , then that numbers


Let the terms are `(a / r) , a , (a × r)`

Addition : `(a / r) + a + (a × r) = 26 ->(1)`

Multiplication : `(a / r) × a × (a × r) = 216`

`=> a^3 = 216`

`=> a = 6`



Now putting `a = 6` in `(1)`, we get

`(6 / r) + 6 + (6 × r) = 26`

`(6 / r) + (6 × r) = 20`

`=> r = 3` or `r = 1/3`

Now, `a = 6` and `r = 3 => (6 / 3) , 6 , (6 × 3) => 2 , 6 , 18`

or `a = 6` and `r = 1/3 => (6 / (1/3)) , 6 , (6 × (1/3)) => 18 , 6 , 2`






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