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 Solution For geometric progression multiplication of 5 terms is 1 and 5 th term is 81 times then the 1 th term.Solution:Your problem -> For geometric progression multiplication of 5 terms is 1 and 5 th term is 81 times then the 1 th term.Let the terms are (a / r^2) , (a / r) , a , (a × r) , (a × r^2)Multiplication : (a / r^2) * (a / r) * a * (a × r) * (a × r^2) = 1=> a^5 = 1=> a = 1Now 5^(th) term is 81 times than the 1^(st) term=> (a × r^2) = 81 (a / r^2)=> r^4 = 81=> r = 3Now, a = 1 and r = 3 => (1 / 3^2) , (1 / 3) , 1 , (1 × 3) , (1 × 3^2) => 0.11 , 0.33 , 1 , 3 , 9 Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me