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 Solution For given geometric progression series 3,6,12,24,48 ,... find 10 th term and addition of first 10 th terms.Solution:Your problem -> For given geometric progression series 3,6,12,24,48 ,... find 10 th term and addition of first 10 th terms.Here a = 3,r = 6/3 = 2We know that, a_n = a × r^(n-1)a_10 = 3 × 2^(10 - 1)= 3 × 512= 1536We know that, S_n = a * (r^n - 1)/(r - 1):. S_10 = 3 × (2^10 - 1)/(2 - 1)=> S_10 = 3 × (1024 - 1)/1=> S_10 = 3 × 1023/1=> S_10 = 3069Hence, 10^(th) term of the given series is 1536 and sum of first 10^(th) term is 3069 Solution provided by AtoZmath.com Any wrong solution, solution improvement, feedback then Submit Here Want to know about AtoZmath.com and me